Question

我想将我的代码从mysql转换为mysqli。但是，我在这里遇到了问题。

mysql代码

 for ($i = $start; $i < $end; $i++) {
                    // make sure that PHP doesn't try to show results that don't exist
                    if ($i == $total_results) {
                        break;
                    }





                    // echo out the contents of each row into a table

                      $bookid = mysql_result($result, $i, 'id');
                    $cover = mysql_result($result, $i, 'cover');

                    echo "
                        <div></div>
                <li>
                    <div id='divborder'>
                        <div id='header'>
                            <a class='caption'  href='page.php?id=$bookid '><img src='$cover' alt='' class='headerBg' /></a>
                        </div>
                    </div>
        </li> ";

                }       
echo "</ul></div>";

我想把它转换成类似的东西

for ($i = $start; $i < $end; $i++) {
    // make sure that PHP doesn't try to show results that don't exist
    if ($i == $total_results) {
        break;
    }
    $i;
                              $book_row = mysqli_fetch_assoc($result);
                              $book_id = $book_row["id"];
                              $book_cover = $book_row["cover"];
                              $book_title = $book_row["title"];
                              $book_auther1 = $book_row["auther1"];                                  
                              $book_auther2 = $book_row["auther2"];




                    echo "
                        <div></div>
                <li>
                    <div id='divborder'>
                        <div id='header'>
                            <a class='caption caption1'data-title='$data_title'  href='book/$book_id'><img src='$book_cover' alt='' class='headerBg' /></a>
                        </div>
                    </div>
        </li> ";

                }       
echo "</ul></div>";

但$i代码中变量mysql中的问题我不知道我将把它放在mysqli

中的哪个位置

Answer 1

$query = "select * from books";

// run the query
$result = mysqli_query($query);

// fetch all the rows
$arrayofrows = mysqli_fetch_all($result, MYSQLI_ASSOC);

// then you can use $i from your for loop
// var_dump($arrayofrows[$i]);

Answer 2

或者类似的东西（来自原始代码）：

<?php
$conn = mysqli_connect('host','username','password','database');
for ($i = $start; $i < $end; $i++) {
        // make sure that PHP doesn't try to show results that don't exist
        if ($i == $total_results) {
        break;
        }


        $query = "select * from tablename where id ='$i'";
        $result = $conn->query($query);
        $data = mysqli_fetch_all($result,MYSQLI_ASSOC);
        $book_id = $data["id"];
        $book_cover = $data["cover"];
        $book_title = $data["title"];
        $book_auther1 = $data["auther1"];                                  
        $book_auther2 = $data["auther2"];   

        echo "
        <div></div>
        <li>
        <div id='divborder'>
        <div id='header'>
        <a class='caption caption1'data-title='$data_title'  href='book/$book_id'><img src='$book_cover' alt='' class='headerBg' /></a>
        </div>
        </div>
        </li> ";
}   
?>

<强>更新

<?php
$con = mysqli_connect('host','username','password','database');
$per_page=5;

if (isset($_GET['page'])) {
$page = $_GET['page'];
} else {
$page=1;
}

// Page will start from 0 and Multiple by Per Page
$start_from = ($page-1) * $per_page;

//Selecting the data from table but with limit
$query = 'SELECT * FROM books LIMIT $start_from, $per_page';
$result = mysqli_query ($con, $query);
$total_records = mysqli_num_rows($result);
$total_pages = ceil($total_records / $per_page);

while ($row = mysqli_fetch_assoc($result)) {
$book_id = $row["id"];
$book_cover = $row["cover"];
$book_title = $row["title"];
$book_auther1 = $row["auther1"];                                  
$book_auther2 = $row["auther2"];    

        echo "
        <div></div>
        <li>
        <div id='divborder'>
        <div id='header'>
        <a class='caption caption1'data-title='$data_title'  href='book/$book_id'><img src='$book_cover' alt='' class='headerBg' /></a>
        </div>
        </div>
        </li> ";

}

//pagination goes here:
echo "<center><a href='".htmlspecialchars($_SERVER["PHP_SELF"])."?page=1'>First Page</a>";
for ($i=1; $i<=$total_pages; $i++) {
echo "<a href='".htmlspecialchars($_SERVER["PHP_SELF"])."?page=".$i."'>".$i."</a>";
}
echo "<center><a href='".htmlspecialchars($_SERVER["PHP_SELF"])."?page=$total_pages'>Last Page</a>";
?>

mysql_result（$ result，$ i，＆＃39; id＆＃39;）相当于mysqli

2 个答案: