Question

我使用socket访问localhost网站。收到以下错误：

HTTP/1.1 408 Request Timeout
Content-Length: 0
Content-Type: text/plain

套接字代码如下：

import socket
mysock = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
mysock.connect(('0.0.0.0',8080))

mysock.send('GET http://localhost:8080/hello HTTP/1.0\r\n')

while True:
    data = mysock.recv(512)
    if (len(data)<1):
        break
    print data
mysock.close()

Answer 1

HTTP请求标头应以两个换行符结尾。如果只发送一个空行，服务器将等到超时。

mysock.send('GET http://localhost:8000/hello HTTP/1.0\r\n\r\n')

使用socket访问localhost网站。错误

1 个答案: