Question

我有一个data.frame，其中包含每个id的线性间隔：

df <- data.frame(id = c(rep("a",3),rep("b",4),rep("d",4)),
                 start = c(3,4,10,5,6,9,12,8,12,15,27),
                 end = c(7,8,12,8,9,13,13,10,15,26,30))

我正在寻找一种有效的功能，它将统一每个id的所有交叉间隔。对于df，结果可能是：

res.df <- data.frame(id = c("a","a","b","d","d","d"),
                     start = c(3,10,5,8,12,27),
                     end = c(8,12,13,10,26,30))

最终，我能够总结每个id的所有联合间隔，以获得它们的总长度：

sapply(unique(res.df$id), function(x) sum(res.df$end[which(res.df$id == x)]-res.df$start[which(res.df$id == x)]+1))

Answer 1

#source("https://bioconductor.org/biocLite.R")
#biocLite("IRanges")
library(IRanges)
df1 <- as(df, "RangedData")

as.data.frame(reduce(df1, by = "id", min.gapwidth = 0.5))

#  space start end width id
#1     1     3   8     6  a
#2     1    10  12     3  a
#3     1     5  13     9  b
#4     1     8  10     3  d
#5     1    12  26    15  d
#6     1    27  30     4  d

合并线性间隔

1 个答案: