Question

我正在尝试使用jquery验证来在表单有效时取消隐藏paypal按钮。我正在使用valid()方法，如下所示。问题是，只要在任何表单元素中按下一个键，就会显示所有错误。如何在不解决所有错误的情况下检查它是否有效？

$('#jValidate').validate({
  rules:{
    username:{
      required:true,
      minlength:6
    },
    email:{
      required:true,
      email:true
    },    
    password:{
      required:true,
      minlength:8
    },
    confirm:{
      required:true,      
      equalTo:"#password"
    }    
  },
  messages:{
    username:{
      required:"Username is required",
      minLength:"Username must be at least 6 characters"
    },
    password:{
      required:"Password is required",
      minLength:"Password must be at least 8 characters"
    },
    confirm:{
      required:"You must confirm your password",
      equalTo:"Password Confirmation does not match"
    }
  }
});
$('#jValidate .form-control').keyup(function(){
  if($('#jValidate').valid()){
    $('#signup').show();
    $('#disabled').hide();  
  }
});

Answer 1

var validator = $('#jValidate').validate({...rules, options});

validator.checkForm() // true if valid, false if not.

jQuery valid（）方法导致显示所有错误

1 个答案: