Question

我希望在我的应用程序第一次在设备中打开时弹出一个对话框。我想在弹出框中显示如何使用该应用程序。如果应用程序第一次打开它会显示对话框，否则只会避免显示对话框。活动也会根据第一次使用或正常使用而改变。首次使用时会显示一个activity1或者它会显示activity2.please帮助我。这是我的活动，在应用程序打开时显示图像

 @Override
 protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_class_name);


new Timer().schedule(new TimerTask() {
    public void run() {
        // here i want to go  to another activity acording to the first time use or normal time

    }
}, 3000);
}

Answer 1

 public class class_name extends AppCompatActivity {
 public static final String MyPREFERENCES2 = "MyPrefs" ;
 SharedPreferences sharedpreferences2;
 public boolean isFirstRun;

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_class_name);


new Timer().schedule(new TimerTask() {
    public void run() {
        checkFirstRun();

    }
}, 3000);
}


public void checkFirstRun() {
System.out.println("its in check first run");
isFirstRun = getSharedPreferences("PREFERENCE2",  MODE_PRIVATE).getBoolean("isFirstRun", true);
if (isFirstRun){
   startActivity(new Intent(class_name.this, new_activity1.class));

    getSharedPreferences("PREFERENCE2", MODE_PRIVATE)
            .edit()
            .putBoolean("isFirstRun", false)
            .commit();

}
else{
     startActivity(new Intent(class_name.this, new_activity2.class));

    }
 }
}

Answer 2

final String FIRST_TIME_KEY = "com.example.app.MainActivity.firstTimeKey";
SharedPreferences sp =     PreferenceManager.getDefaultSharedPreferences(this);
boolean isFirstTime = sp.getBoolean(FIRST_TIME_KEY, false);
if(isFirstTime) {
    SharedPreferences.Editor edit = sp.edit();
    edit.putBoolean(FIRST_TIME_KEY, true);
    edit.apply();

//show the dialog
}

当我第一次启动我的应用程序时，第一次如何弹出一个对话框？

2 个答案: