Question

伙计们我是hibernate的新手..我正在尝试使用hibernate在java中运行插入函数但是它给了我异常..任何帮助..在此先感谢

＆＃13;

Exception in thread "main" java.lang.NoSuchFieldError: namingStrategy
	at org.hibernate.cfg.AnnotationConfiguration.reset(AnnotationConfiguration.java:250)
	at org.hibernate.cfg.Configuration.<init>(Configuration.java:125)
	at org.hibernate.cfg.Configuration.<init>(Configuration.java:119)
	at org.hibernate.cfg.AnnotationConfiguration.<init>(AnnotationConfiguration.java:108)
	at InsertData.main(InsertData.java:11)

＆＃13;

＆＃13; DataProvider.java

＆＃13;

import javax.persistence.*;

@Entity
@Table(name="dataprovider")
public class DataProvider {
	
	@Id @GeneratedValue
	@Column(name="id")
	private int user_id;
	@Column(name="name")
	private String user_name;
	@Column(name="description")
	private String user_desc;
	
	
	public int getUser_id() {
		return user_id;
	}
	public void setUser_id(int user_id) {
		this.user_id = user_id;
	}
	public String getUser_name() {
		return user_name;
	}
	public void setUser_name(String user_name) {
		this.user_name = user_name;
	}
	public String getUser_desc() {
		return user_desc;
	}
	public void setUser_desc(String user_desc) {
		this.user_desc = user_desc;
	}
	

}

＆＃13;

InsertData.java

＆＃13;

import javax.persistence.*;

@Entity
@Table(name="dataprovider")
public class DataProvider {
	
	@Id @GeneratedValue
	@Column(name="id")
	private int user_id;
	@Column(name="name")
	private String user_name;
	@Column(name="description")
	private String user_desc;
	
	
	public int getUser_id() {
		return user_id;
	}
	public void setUser_id(int user_id) {
		this.user_id = user_id;
	}
	public String getUser_name() {
		return user_name;
	}
	public void setUser_name(String user_name) {
		this.user_name = user_name;
	}
	public String getUser_desc() {
		return user_desc;
	}
	public void setUser_desc(String user_desc) {
		this.user_desc = user_desc;
	}
	

}

＆＃13;

的hibernate.cfg.xml

＆＃13;

<?xml version='1.0' encoding='utf-8'?>
<hibernate-configuration>

<session-factory>
 
<!-- Related to the connection START -->
<property name="connection.driver_class">com.mysql.jdbc.Driver </property>
<property name="connection.url">jdbc:mysql://localhost:3306/mydb </property>
<property name="connection.user">root </property>
<property name="connection.password">root</property>
<!-- Related to the connection END -->
 
<!-- Related to hibernate properties START -->
<property name="show_sql">true</property>
<property name="dialet">org.hibernate.dialet.MYSQLDialet</property>
<property name="hbm2ddl.auto">create</property>
<!-- Related to hibernate properties END-->
 
<!-- Related to mapping START-->
<mapping resource="user.hbm.xml" />
<!-- Related to the mapping END -->
 
</session-factory>
</hibernate-configuration>

＆＃13;

Answer 1

对于注释，您需要将user.hbm.xml更改为packagename.classname

<!-- Related to mapping START-->
<mapping resource="user.hbm.xml" />
<!-- Related to the mapping END -->

您必须在该案例中使用您的包名。

<mapping class="yourPackageName.DataProvider" />

其中，

yourPackageName = com.something。

DataProvider =您的班级名称

相关链接：http://www.mkyong.com/hibernate/hibernate-one-to-one-relationship-example-annotation/

在hibernate应用程序中运行insert fiunction的异常

1 个答案: