我正在努力让我的查询在不同的表列HomeTeam和AwayTeam中查找TeamCode,如果AwayTeam或HomeTeam在HomeTeam或AwayTeam中没有35,则返回Team列。
此代码仅查找匹配表中不存在的TeamCode,我需要这样做,它只显示35不存在的行。
SELECT Team
FROM club
WHERE TeamCode NOT IN (SELECT DISTINCT
HomeTeam FROM matches);
答案 0 :(得分:1)
我不知道您希望哪个列与35不同,但要将其更改为所需的列名称:
'use strict';
var obj = [{'id': 0, 'review': 'Test1', 'author': 'Bob1'},{'id': 1, 'review': 'Test2', 'author': 'Bob2'},{'id': 2, 'review': 'Test3', 'author': 'Bob3'}];
$(function () {
var html = '';
var first = true;
$.each(obj, function (i, v) {
html += '<div id="review_' + i + '" class="review ' + (first ? '' : 'hide') + '">';
html += '<p>' + v.review + '</p>';
html += '<p class="small">' + v.author + '</p>';
html += '</div>';
first = false;
})
$('#review_container').html(html);
cycleReviews(0);
var t_out;
function cycleReviews(idx) {
clearTimeout(t_out);
t_out = setTimeout(function () {
console.log(idx)
if(idx == obj.length) {
console.log('reload')
idx = 0;
}
$('.review').animate({opacity: '0'}, function () {
$('.review').addClass('hide');
$('#review_'+ (idx)).css('opacity', '0.0').removeClass('hide').animate({opacity: '1.0'});
cycleReviews(idx+1);
});
}, 2000);
}
});
或不存在:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container text-center home-2">
<h1 class="hero">Customer Reviews</h1>
<div class="bullets"><span id="bullet_1">•</span> <span id="bullet_2">◦</span> <span id="bullet_3">◦</span></div>
<div id="review_container">
</div>
<p class="green">A happy client</p>
</div>