当CASE语句为true时,SQL返回另一个表的值

时间:2016-03-20 02:48:39

标签: sql postgresql

我想编写一个SQL语句,该语句根据CASE语句返回一个值,该语句有三种可能的结果。

1)如果列值以'C0'开头,则它返回表中两列的串联

2)如果列以'L0'开头,则取该行中另一列(_PARENT_PROJECT_NUMBER)中的值,并查看该值是否位于另一个表中。如果不是,则返回值_PARENT_PROJECT_NUMBER。

3)如果_PARENT_PROJECT_NUMBER确实驻留在另一个表中,则返回另一个表“Rollup_Project_Mapping”中“Rollup_Project”列中的值。

我在下面写的声明工作正常,但第12行"Rollup_Project_Mapping"."Rollup_Project"除外,如果在另一个表中找到_PARENT_PROJECT_NUMBER,我希望它返回另一个表的值。以下是错误消息:

ERROR:  syntax error at or near "FROM"
LINE 12:      FROM "Rollup_Project_Mapping"."Rollup_Project"

当CASE语句的这部分为真时,有谁知道如何在其他表中返回值?

SELECT
CASE 
  WHEN LEFT("_PROJECT_NUMBER",2)='C0' THEN
    '('||"_PROJECT_NUMBER"||') '||"_PROJECT_DESCRIPTION"
  WHEN LEFT("_PROJECT_NUMBER",2)='L0' THEN
    CASE
      WHEN (SELECT "Rollup_Project" FROM "Project_Rollup_Mapping" WHERE "PA_ACCOUNTED_TEST"."_PARENT_PROJECT_NUMBER" = "Project_Rollup_Mapping"."Project") IS NOT NULL THEN
        "Rollup_Project_Mapping"."Rollup_Project"
    ELSE "_PARENT_PROJECT_NUMBER"
    END
END AS Rollup_Project2
FROM "PA_ACCOUNTED_TEST";

2 个答案:

答案 0 :(得分:4)

您只能使用一组WHEN / THEN语句和EXISTS

SELECT (CASE WHEN LEFT("_PROJECT_NUMBER",2) = 'C0'
             THEN '('||"_PROJECT_NUMBER"||') '||"_PROJECT_DESCRIPTION"
             WHEN LEFT("_PROJECT_NUMBER",2) = 'L0' AND
                  EXISTS (SELECT "Rollup_Project" FROM "Project_Rollup_Mapping" WHERE "PA_ACCOUNTED_TEST"."_PARENT_PROJECT_NUMBER" = "Project_Rollup_Mapping"."Project")
                  THEN (SELECT "Rollup_Project" FROM "Project_Rollup_Mapping" WHERE "PA_ACCOUNTED_TEST"."_PARENT_PROJECT_NUMBER" = "Project_Rollup_Mapping"."Project")
             ELSE "_PARENT_PROJECT_NUMBER"
       END) AS Rollup_Project2
FROM "PA_ACCOUNTED_TEST";

答案 1 :(得分:0)

我根据@Gordon Linoff的答案修改了原始的SQL语句,以防有人想要它作为另一种选择:

SELECT
CASE 
  WHEN LEFT("_PROJECT_NUMBER",2)='C0' THEN
    '('||"_PROJECT_NUMBER"||') '||"_PROJECT_DESCRIPTION"
  WHEN LEFT("_PROJECT_NUMBER",2)='L0' AND (SELECT "Rollup_Project" FROM "Project_Rollup_Mapping" WHERE "PA_ACCOUNTED_TEST"."_PARENT_PROJECT_NUMBER" = "Project_Rollup_Mapping"."Project") IS NOT NULL THEN
    (SELECT "Rollup_Project" FROM "Project_Rollup_Mapping" WHERE "PA_ACCOUNTED_TEST"."_PARENT_PROJECT_NUMBER" = "Project_Rollup_Mapping"."Project")
  ELSE "_PARENT_PROJECT_NUMBER"
END AS Rollup_Project2
FROM "PA_ACCOUNTED_TEST";