我正在寻找一个方法小组empNumber，似乎无法找到方法
这是我目前的查询：
SELECT EmpNumber, [Match], [NonMatch], [Base], [SRA], [SRS]
from
(select a.empnumber, TT_GB.MAXDate, a.TT_Plan, a.TT_Ratio
from table_1 as a
inner join
(select b.empnumber, b.TT_Plan, MAX(b.TT_Date) as MAXDate
from table_1 as b
group by b.empnumber, b.TT_Plan) TT_GB
ON a.EmpNumber = TT_GB.EmpNumber AND a.TT_Plan = TT_GB.TT_Plan AND a.TT_Date = TT_GB.MAXDate
) M
PIVOT
(
SUM(TT_Ratio)
FOR [TT_Plan] IN ([Match], [NonMatch], [Base], [SRA], [SRS])
) P
这就是我在表格中的内容
=============================================
EmpNumber TT_Plan TT_Date TT_Ratio
1 Base 2008-05-11 11
1 Base 2015-08-22 12
1 Base 2010-07-09 13
1 Match 2003-01-23 15
1 Match 2000-11-17 14
1 NonMatch 2014-09-22 19
1 NonMatch 2015-02-15 18
1 NonMatch 2009-08-13 17
1 SRA 2005-07-16 2
1 SRS 2006-04-12 3
2 Base 2008-08-08 5
2 Base 2009-09-09 7
2 Base 2010-10-10 4
2 NonMatch 2011-01-01 8
2 NonMatch 2012-12-12 6
2 NonMatch 2007-07-07 9
Desired output
==============
EmpNumber Match NonMatch Base SRA SRS
1 15 18 12 2 3
2 0 6 4 0 0
但我现在所拥有的就是这个，我想要的就是按照上面的EmpNumber分组
=============================================================================
EmpNumber Match NonMatch Base SRA SRS
1 15 NULL NULL NULL NULL
1 NULL NULL NULL 2 NULL
1 NULL NULL NULL NULL 3
2 NULL NULL 4 NULL NULL
2 NULL 6 NULL NULL NULL
1 NULL 18 NULL NULL NULL
1 NULL NULL 12 NULL NULL
答案 0 :(得分：1)
我不认为这是最好的解决方案，但你可以通过创建如下的别名表来实现：
Select t.EmpNumber, Sum(t.Match), Sum(t.NonMatch), Sum(t.Base), Sum(t.SRA), Sum(t.SRS) from
(
SELECT EmpNumber, [Match], [NonMatch], [Base], [SRA], [SRS]
from
(select a.empnumber, TT_GB.MAXDate, a.TT_Plan, a.TT_Ratio
from table_1 as a
inner join
(select b.empnumber, b.TT_Plan, MAX(b.TT_Date) as MAXDate
from table_1 as b
group by b.empnumber, b.TT_Plan) TT_GB
ON a.EmpNumber = TT_GB.EmpNumber AND a.TT_Plan = TT_GB.TT_Plan AND a.TT_Date = TT_GB.MAXDate
) M
PIVOT
(
SUM(TT_Ratio)
FOR [TT_Plan] IN ([Match], [NonMatch], [Base], [SRA], [SRS])
) P
) t group by t.EmpNumber
答案 1 :(得分：1)
所以我之前写的是
declare @table_1 table ( EmpNumber int, TT_Plan varchar(20), TT_Date date, TT_Ratio int )
insert @table_1
values
(1,'Base','2008-05-11',11)
,(1,'Base','2015-08-22',12)
,(1,'Base','2010-07-09',13)
,(1,'Match','2003-01-23',15)
,(1,'Match','2000-11-17',14)
,(1,'NonMatch','2014-09-22',19)
,(1,'NonMatch','2015-02-15',18)
,(1,'NonMatch','2009-08-13',17)
,(1,'SRA','2005-07-16',2)
,(1,'SRS','2006-04-12',3)
,(2,'Base','2008-08-08',5)
,(2,'Base','2009-09-09',7)
,(2,'Base','2010-10-10',4)
,(2,'NonMatch','2011-01-01',8)
,(2,'NonMatch','2012-12-12',6)
,(2,'NonMatch','2007-07-07',9)
SELECT EmpNumber, [Match], [NonMatch], [Base], [SRA], [SRS]
from
(select a.empnumber,a.TT_Plan, a.TT_Ratio
from @table_1 as a
inner join
(select b.empnumber, b.TT_Plan, MAX(b.TT_Date) as MAXDate
from @table_1 as b
group by b.empnumber, b.TT_Plan) TT_GB
ON a.EmpNumber = TT_GB.EmpNumber AND a.TT_Plan = TT_GB.TT_Plan AND a.TT_Date = TT_GB.MAXDate
) M
PIVOT
(
SUM(TT_Ratio)
FOR [TT_Plan] IN ([Match], [NonMatch], [Base], [SRA], [SRS])
) P
结果是
EmpNumber Match NonMatch Base SRA SRS
----------- ----------- ----------- ----------- ----------- -----------
1 15 18 12 2 3
2 NULL 6 4 NULL NULL
答案 2 :(得分：1)
您可以使用窗口功能首先过滤每组的最新记录。
然后工作查询变为：
select *
from (
select empnumber, tt_plan, tt_ratio
from (
select *,
rank() over (partition by empnumber, tt_plan
order by tt_date desc) as rnk
from table_1) as t1
where rnk = 1) as m
pivot (
sum(TT_Ratio)
for TT_Plan in ([Match], [NonMatch], [Base], [SRA], [SRS])
) as p
输出：
+-----------+--------+----------+------+--------+--------+
| empnumber | Match | NonMatch | Base | SRA | SRS |
+-----------+--------+----------+------+--------+--------+
| 1 | 15 | 18 | 12 | 2 | 3 |
| 2 | (null) | 6 | 4 | (null) | (null) |
+-----------+--------+----------+------+--------+--------+