MVC5：迭代ViewModel

Question

在我的viewmodel中，还有其他一些属性，我有这个：

public int AuthorStatus {get; set;}

public string AuthorStatusLabelClass
{
    get
    {
        switch (AuthorStatus)
        {
            case 1:
                return "label-success";
            case 0:
                return "label-danger";
            case 2:
                return "label-warning";
            default:
                return "label-default";
        }
    }
    set
    {

    }
}

public IQueryable<VM_Authors> AuthorList { get; set; }

如何访问控制器中的AuthorStatusLabelClass;

    var vm = new ViewModels.VM_Authors();
    vm.Categories = new SelectList(db.AuthorCategories, "CategoryID", "CategoryName");
    vm.AuthorList = (from a in db.Authors
                     select new ViewModels.VM_Authors
                     {
                         FirstName = a.FirstName,
                         LastName = a.LastName,
                         Email = a.Email,
                         AuthorStatusLabelClass = ####HOW_SHOULD_I_RETRIEVE_IT_HERE####

这样我就可以在我的视图中使用它：

        @foreach (var item in Model.AuthorList)
        {
        <tr>
            <td><span class="label @item.AuthorStatusLabelClass">@item.AuthorStatus</span></td>
            <td><img src="" class="img-circle" /></td>
            <td><span class="text-semibold">@item.FirstName @item.LastName</span></td>
            <td>@item.SelectedCategoryID</td>
            <td></td>
        </tr>
        }

可能是我的整个方法有所不同？任何帮助将不胜感激！

Answer 1

修改

由于您提到AuthorStatusLabelClass不是数据库表的列和之一，它完全取决于您的AuthorStatus，因此您不需要完全分配它。只需：

select new ViewModels.VM_Authors
 {
     FirstName = a.FirstName,
     LastName = a.LastName,
     Email = a.Email,
     AuthorStatus = a.AuthorStatus //assign this

当您在AuthorStatusLabelClass中获得View时，只需直接获取该AuthorStatus，并且上面指定的AuthorStatusLabelClass将会在View中归还setter {1}}。

<强>原始

您似乎未在AuthorStatusLabelClass中设置select new ViewModels.VM_Authors { FirstName = a.FirstName, LastName = a.LastName, Email = a.Email, AuthorStatusLabelClass = //This is a set ####HOW_SHOULD_I_RETRIEVE_IT_HERE#### ，因此您无法执行此操作：

AuthorStatusLabelClass

带有setter的

private string _authorStatusLabelClass = ""; public string AuthorStatusLabelClass { get { switch (AuthorStatus) { case 1: _authorStatusLabelClass = "label-success"; case 0: _authorStatusLabelClass = "label-danger"; case 2: _authorStatusLabelClass = "label-warning"; default: _authorStatusLabelClass = "label-default"; } return _authorStatusLabelClass; } set { _authorStatusLabelClass = value; } } 可能如下所示：

AuthorStatus

此外，由于您需要先将AuthorStatusLabelClass设置为某个号码，然后才能检索AuthorStatusLabelClass，因此如果没有AuthorStatus，您可能无法正确获取AuthorStatusLabelClass }。课程indexer中您可能需要的是public AuthorStatusLabelClass this[int index] { //thus you could give index as an input for this instance get { switch (index) { case 1: return "label-success"; case 0: return "label-danger"; case 2: return "label-warning"; default: return "label-default"; } } } ：

vm.AuthorList = (from a in db.Authors
                 select new ViewModels.VM_Authors
                 {
                     FirstName = a.FirstName,
                     LastName = a.LastName,
                     Email = a.Email,
                     AuthorStatusLabelClass = a.AuthorStatusLabelClass[a.AuthorStatus]

并像这样使用它：

public wizard()
{
    InitializeComponent();
    var intro = new intro();
    wizardframe.NavigationService.Navigate(intro);
} // this is the intro page.

private void ileri_b1_Click(object sender, RoutedEventArgs e)
{
    string introtest = "intro";
    if (introtest == "intro")
    {
        var wpage2 = new wpage2();
        wizardframe.NavigationService.Navigate(wpage2);
        introtest = "wpage2";
    }
    else if (introtest == "wpage2")
    {        
        string fileName = String.Format(@"{0}\temp\aciklama.txt", Environment.CurrentDirectory);
        StreamWriter file = new StreamWriter(fileName);
        file.Write(attext);
        file.Close(); // this is the "Ileri" Button click event.Just saving file.
    }

Answer 2

我可以看到你的AuthorStatusLabelClass有吸气剂和一个空的二传手。 Getter依赖于AuthorStatus属性。您所要做的就是正确设置AuthorStatus属性。

select new ViewModels.VM_Authors
 {
     FirstName = a.FirstName,
     LastName = a.LastName,
     Email = a.Email,
     AuthorStatus = ### SETUP status and don't worry about AuthorStatusLabelClass ###