Question

我有以下场景的测试用例：

1）导航到网站。
2）输入Login Credential 3）点击登录。

在我的应用程序中登录后，我为最终用户提供了提示弹出窗口。我使用窗口处理程序来关闭它，但问题是有时selenium运行速度太快，以至于它在可见之前点击它。任何帮助将不胜感激。

Wait<WebDriver> wait = new FluentWait<WebDriver>(driver)
                .withTimeout(60, TimeUnit.SECONDS)
                .pollingEvery(2, TimeUnit.SECONDS)
                .ignoring(NoSuchElementException.class);
    String mainWindowHandle = driver.getWindowHandle();
            driver.switchTo().parentFrame();
            wait.until(ExpectedConditions.urlContains("client/default"));
            wait.until(new ExpectedCondition<Boolean>() {
                @Override
                public Boolean apply(WebDriver d) {
                    System.out.println(String.format("Window size is %d", d.getWindowHandles().size()));
                    return (d.getWindowHandles().size() == 1);
                }
            });

            for (String activeHandle : driver.getWindowHandles()) {
                if (!activeHandle.equals(mainWindowHandle)) {
                    driver.switchTo().window(activeHandle);
                }
            }

            driver.findElement(By.xpath(elementLocator("popup_close_button"))).click();
           driver.switchTo().window(mainWindowHandle);  // switch back to parent window

Answer 1

参考此代码（摘自 here并修改过）：

如果你想让它一直工作，直到弹出出来，然后添加一些代码，如下所示：

int flag=0,wait=0;

while(flag==0 && wait<60){
try{

String parentWindowHandler = driver.getWindowHandle(); // Store your parent window
String subWindowHandler = null;

Set<String> handles = driver.getWindowHandles(); // get all window handles
Iterator<String> iterator = handles.iterator();
while (iterator.hasNext()){
subWindowHandler = iterator.next();
}
driver.switchTo().window(subWindowHandler); // switch to popup window
                                        // perform operations on popup
driver.close();///close pop up

driver.switchTo().window(parentWindowHandler);  // switch back to parent window
 //statements executed successfully, now exit by flag set to 1
 flag=1;

}
catch(exception e){//wait for one second
driver.manage().timeouts().implicitlyWait(1, TimeUnit.SECONDS);
wait++;
}

if(wait==60){
JOptionPane.showMessageDialog(null,"Failed to detect pop up after 60 seconds."); 
}


}

Answer 2

发表评论后，声明关闭按钮不会出现在新窗口或标签中。相反，它是登录后的下一页。更新答案以利用预先存在的ExpectedConditions元素，该元素应该（希望）解决问题。

 /**
  * Performs application Login.
  * @param driver WebDriver to act upon.
  */
  public void login(WebDriver driver) {
     //Perform Login function

     //1.  Identify the lookup we're going to use for the button.
     By closeButtonLookup = elementLocator("popup_close_button");

     //2.  Set up the Wait object with a reasonable timout value.
     WebDriverWait wait = new WebDriverWait(driver, 30);

     //3.  Try to resolve the close button (from the current page/window/tab) after Selenium believes it to be a viable click target.
     WebElement closeButton = wait.until(ExpectedConditions.elementToBeClickable(closeButtonLookup));
     System.out.println("Close button valid!  Proceeding to click!");

     //4.  Click the button
     closeButton.click();
     System.out.println("I clicked the close button!");

     //Continue program
 }

在Selenium登录后立即处理弹出窗口

2 个答案: