Django NoReverseMatch at / qw-1 /

Question

我是django的新手，并且使用slug ，现在我很困惑如何使用ID参数并转换为slug

URL.py

 url(r'^deletePost/(?P<slug>[\w-]+)/$', views.delete_post, name='delete_post')

模板

<form method="POST" action="{% url 'delete_post' id=post.id %}">{% csrf_token %}

    <button type="submit" class="btn btn-danger"> &nbsp Delete</button>
</form>

Views.py

def delete_post(request,slug):
    posts=Post.objects.get(slug=slug)
    if request.method == 'POST':
        posts.delete()
        return redirect("home")

我如何使用slug＆amp; id删除创建的帖子

感谢任何帮助。提前致谢

参考错误

Answer 1

在我的意见中，你不想将id转换为slug。您可以使应用程序足够灵活，以便可以slug或id删除。您只需要相应地处理参数。

所以，你可以这样做：

urls.py

url(r'^deletePost/(?P<slug>[\w-]+)/$', views.delete_post, name='delete_post_by_slug'),
url(r'^deletePost/(?P<id>[0-9]+)/$', views.delete_post, name='delete_post_by_id')

在观点中：

def delete_post(request, slug=None, id=None):
    if slug:
        posts=Post.objects.get(slug=slug)
    if id:
        posts=Post.objects.get(id=id)
    #Now, your urls.py would ensure that this view code is executed only when slug or id is specified

    #You might also want to check for permissions, etc.. before deleting it - example who created the Post, and who can delete it.
    if request.method == 'POST':
        posts.delete()
        return redirect("home")

请注意，您可以将2个URL模式压缩为单个模式 - 但这种方法使其可读且易于理解。一旦你对django框架等感到满意，我会让你弄清楚URL合并。

Answer 2

如果你想同时使用slug和id，你的URL模式应如下所示：

url(r'^deletePost/(?P<slug>[\w-]+)-(?P<id>[0-9]+)/$',
    views.delete_post, name='delete_post')

您的观点应如下所示：

def delete_post(request, **kwargs):
    # Here kwargs value is {'slug': 'qw', 'id': '1'}
    posts = Post.objects.get(**kwargs)
    if request.method == 'POST':
        posts.delete()
        return redirect('home')
    # ... (I guess this view does not end here)

您的模板还必须同时设置：

<form method="POST" action="{% url 'delete_post' slug=post.id id=post.id %}">{% csrf_token %}

    <button type="submit" class="btn btn-danger"> &nbsp Delete</button>
</form>