这是我想要的,但是有更简单,更优雅的方法吗?
IF OBJECT_ID('TEMPDB..#test') IS NOT NULL DROP TABLE #test;
CREATE TABLE #test
(
userAcc VARCHAR(100),
game VARCHAR(100),
amount INT
);
INSERT INTO #test
values
('jas', 'x', 10),
('jas', 'y', 100),
('jas', 'z', 20),
('sam', 'j', 10),
('sam', 'q', 5);
--initial table sample
SELECT userAcc,
game,
amount
FROM #test;
WITH
X AS
(
SELECT rn = ROW_NUMBER() OVER (PARTITION BY userAcc ORDER BY game),
userAcc,
game,
amount,
rk = RANK() OVER (PARTITION BY userAcc ORDER BY amount DESC)
FROM #test
),
Y AS
(
SELECT RK,userAcc,
game,
targ = rn
FROM X
WHERE rk = 1
)
SELECT X.userAcc,
X.game,
X.amount,
ISNULL(Y.targ,0)
FROM X
LEFT OUTER JOIN Y
ON
X.userAcc = Y.userAcc AND
X.rn = Y.rk
ORDER BY X.userAcc,X.rn;
它返回:
这是初始表:
脚本正在做的是:
答案 0 :(得分:4)
您不需要join
。你可以使用积累。
如果我理解正确:
select userAcc, game, amount,
isnull( (case when rn = 1
then max(case when rk = 1 then rn end) over (partition by userAcc)
end),0) as newcol
from (select t.*,
ROW_NUMBER() OVER (PARTITION BY userAcc ORDER BY game) as rn,
RANK() OVER (PARTITION BY userAcc ORDER BY amount DESC) as rk
from #test t
) t
order by userAcc;