Question

程序用于将程序参数解析为几何形状。

Circle（C）：1 arg [radius]
五角大楼（P）：1 arg [side]
Square，Rhombus，Rect（Q）：5 args [a，b，c，d，angleA]（程序选择哪个一个基于args生成）

我的问题是在控制台中打印异常/错误的顺序。

public static void main(String[] args)
{
    if (args.length > 0)
    {
        int readerIndex = 0; // currently read argument

        for (char symbol : args[readerIndex++].toCharArray())
        {
            ShapeType type = null; // Enum for C, P or Q.
            int toRead = 0; // How many args should we read.
            int read = 0; // How many we alredy read.

            try
            {
                type = ShapeType.bySymbol(symbol); // C, P or Q.
                toRead = type.getDataFormatSize(); // number of args to read.

                double[] vars = new double[toRead];
                // converting
                for (int i = 0; i < vars.length; ++i)
                {
                    vars[i] = Double.valueOf(args[readerIndex + i]);
                    ++read;
                }
                // This will create and print proper shape for given data.
                System.out.println(ShapeFactory.generateShape(type, vars).toString());
            }
            catch (ShapeSymbolException e) // thrown if letter is not a shape symbol.
            {
                e.printStackTrace();
            }
            catch (ArrayIndexOutOfBoundsException e) // when we are out of args.
            {
                System.err.println("Too few arguments to generate " + type.name() + "!");
            }
            catch (NumberFormatException e) // When we can't convert to double.
            {
                System.err.println("Could not convert String to double while generating " + type.name() + ". Offender: " + args[readerIndex + read] + " | Dumping arguments: " + Arrays.toString(Arrays.copyOfRange(args, readerIndex, readerIndex + toRead)));
            }
            catch (ShapeGenException e) // When data passed to ShapeFactory cannot generate proper shape from it.
            {
                e.printStackTrace();
            }
            finally
            {
                readerIndex += toRead; // In any case (exception or not) - we will be skipping args that were supposed to be parsed to shape.
            }
        }
    }
}

现在输入数据：

C 10

CIRCLE (C) | Radius = 10.0

CQP 3 2 4 2 4 90 50

CIRCLE (C) | Radius = 3.0
QUADRILATERAL (Q) | RECTANGLE | Side A = 2.0 | Side B = 4.0
PENTAGON (P) | Side = 50.0

CQPPQ 3 2 4 2 4 90 50 w2 2 2 2 2 90

CIRCLE (C) | Radius = 3.0
QUADRILATERAL (Q) | RECTANGLE | Side A = 2.0 | Side B = 4.0
PENTAGON (P) | Side = 50.0
Could not convert String to double while generating PENTAGON. Offender: w2 | Dumping arguments: [w2]
QUADRILATERAL (Q) | SQUARE | Side = 2.0

“无法转换...”部分随机打印在控制台中。它通常是它应该在的位置（顺序排在第4位），但在其他打印之前或之后出现的次数约为1/3。

我可以理解它稍后打印，但更早？我什么都想不到。

为什么会这样？

Answer 1

System.err和System.out是两个独立的流 - 订单仅在单个流中得到保证。由于两个流都以未定义的方式合并到您的控制台中，因此打印到两个流的文本的顺序可能会发生变化。如果您将所有内容打印到System.out，那么您的输出就会很好。

异常和错误以错误的顺序打印

1 个答案: