Question

我试图在angularjs中获得对象数组的精确关键匹配，而不是我得到所有匹配的结果。我怎样才能做到这一点？

这是控制器代码： -

var myApp = angular.module('myApp', []);

myApp.controller('ToddlerCtrl', function ($scope,$filter) {


 $scope.toddlers = [
{
  "name": "Toddler One",
  "tid": "85",

},
{
  "name": "Toddler Two",
  "tid": "485",

},
{
  "name": "Toddler Three",
  "tid": "4485",

} ,
{
  "name": "Toddler Four",
  "tid": "8845",

}
];

  var found = $filter('filter')($scope.toddlers, 85  );
    console.log(found); // I want the exact match i.e. ("Toddler one" with "85" only) but I am getting 3 results.



});

here is the Plnkr

Answer 1

解决方案非常简单：添加一个true作为第三个参数，表明搜索需要精确。请注意，85不会匹配任何东西，你需要输入'85'：

var found = $filter('filter')($scope.toddlers, '85' , true);

有关详细信息，请查看文档中的比较器参数：Angular Filter

我们怎样才能在angularjs中获得对象数组的精确关键匹配

1 个答案: