Question

以下是我正在进行的名为测试的集合，我需要让所有正在进行DOB的人员参加＆＃34; 24-04-1973＆＃34;

 {
        "year": "1973",
        "allPersons": [
            {
                "name": "First guy",
                "DOB": "24-04-1973"
            },
            {
                "name" : "Second guy",
                "DOB":  "02-12-1973"
            }     
            {
                "name": "Third guy",
                "DOB": "13-01-1973"
            },
            {
                "name": "Fourth guy",
                "DOB": "24-04-1973"
            },
            {
                "name": "Fifth guy",
                "DOB": "24-04-1973"
            },
        ]
    }

但我只能通过以下查询从allPersons数组中获取第一个对象

 db.testing.find(
       {
              "allPersons.DOB":"24-04-1973"
       },
       {
              _id:0,"allPersons":
              {
                     $elemMatch:
                     {
                            "DOB":'24-04-1973'
                     }
              }
       }
).pretty();

以上查询的结果

{
        "allPersons" : [
                {
                        "name" : "First guy",
                        "DOB" : "24-04-1973"
                }
        ]
}

但我期望获得的结果是让所有DOB "24-04-1973"的人都在下面

  {
            "allPersons" : [
                    {
                            "name" : "First guy",
                            "DOB" : "24-04-1973"
                    },
                    {        
                            "name" : "Fourth guy",
                            "DOB" : "24-04-1973"
                    },
                    {
                            "name" : "Fifth guy",
                            "DOB" : "24-04-1973"
                    }
            ]
    }

是否有人知道正确的查询以生成上述类型的结果

mongo Db版本2.6.11

我是新来的，请原谅，如果它是愚蠢的

Answer 1

尝试以下脚本：

db.doc.aggregate([
    {$unwind:"$allPersons"},
    {$match:{"allPersons.DOB":"24-04-1973"}},
    {$group:{_id:{id:"$_id", year:"$year"}, allPersons:{$push:"$allPersons"}}},
    {$project:{_id:0, allPersons:1}}  
])

会发出：

{ 
    "allPersons" : [
        {
            "name" : "First guy", 
            "DOB" : "24-04-1973"
        }, 
        {
            "name" : "Fourth guy", 
            "DOB" : "24-04-1973"
        }, 
        {
            "name" : "Fifth guy", 
            "DOB" : "24-04-1973"
        }
    ]
}

从mongodb集合中获取对象数组中的匹配对象？

1 个答案: