我设法在这样的表中转换了一些不可读的数据。 SQL
表表示多层平面层次结构。问题是,如何根据下面的级别和结构生成一个普通的参差不齐的sql parent-child
层次结构:ID | Element | Parent
?
答案 0 :(得分:2)
您可以使用层次结构和自动递增ID创建一个新表,如下所示:
create table hierarchy (
id int not null identity (1,1) primary key,
element varchar(100),
parent int
);
然后你会先将1级元素添加到它,因为它们没有父级:
insert into hierarchy (element, parent)
select distinct f.level1, null
from flat f;
现在您已为这些元素生成 id 值,您可以添加下一个级别,如下所示:
insert into hierarchy (element, parent)
select distinct f.level2, h1.id
from hierarchy h1
inner join flat f
on f.level1 = h1.element
where h1.parent is null;
这种模式可以重复到下一个级别:
insert into hierarchy (element, parent)
select distinct f.level3, h2.id
from hierarchy h1
inner join hierarchy h2
on h2.parent = h1.id
inner join flat f
on f.level1 = h1.element
and f.level2 = h2.element
where h1.parent is null;
insert into hierarchy (element, parent)
select distinct f.level4, h3.id
from hierarchy h1
inner join hierarchy h2
on h2.parent = h1.id
inner join hierarchy h3
on h3.parent = h2.id
inner join flat f
on f.level1 = h1.element
and f.level2 = h2.element
and f.level3 = h3.element
where h1.parent is null;
insert into hierarchy (element, parent)
select distinct f.level5, h3.id
from hierarchy h1
inner join hierarchy h2
on h2.parent = h1.id
inner join hierarchy h3
on h3.parent = h2.id
inner join hierarchy h4
on h4.parent = h3.id
inner join flat f
on f.level1 = h1.element
and f.level2 = h2.element
and f.level3 = h3.element
and f.level4 = h4.element
where h1.parent is null;
insert into hierarchy (element, parent)
select distinct f.level6, h3.id
from hierarchy h1
inner join hierarchy h2
on h2.parent = h1.id
inner join hierarchy h3
on h3.parent = h2.id
inner join hierarchy h4
on h4.parent = h3.id
inner join hierarchy h5
on h5.parent = h4.id
inner join flat f
on f.level1 = h1.element
and f.level2 = h2.element
and f.level3 = h3.element
and f.level4 = h4.element
and f.level5 = h5.element
where h1.parent is null;
......等等,直到需要的水平。