Question

我有这个程序，我需要制作一个随机生成的10个数字的行，我需要找到行上最大，最小，第一个和最后一个数字。我已经有了数字线，我找到了最大和最小的数字。我需要帮助找出如何找到线上的第一个和最后一个数字。这是我到目前为止的代码：

// variables
    Random generator = new Random();
    int max = 0, min = 100, random, first, last;

    // for
    System.out.println("Here are 10 random numbers: \n");
    for (int count = 1; count <= 10; count++) {

        // get random number and output
        random = 1 + generator.nextInt(100);
        System.out.print(random + " ");

        // Max number
        if (random > max)
            max = random;

        // Min number
        if (random < min)
            min = random;
    }

    // output
    System.out.print("\n\nThe first number is " + last);
    System.out.print("\nThe last number is " + first);
    System.out.println("\nThe largest random number is " + max);
    System.out.print("The smallest random number is " + min);

Answer 1

Collection和Collections是存储对象并在其上应用某些算法的非常好的工具。

试试这个：

Random generator = new Random();
final int MIN = 0, MAX = 100;
LinkedList<Integer> numberLine = new LinkedList<>();

for (int count = 1; count <= 10; count++) {
    int random = generator.nextInt(MAX) + 1;
    numberLine.add(random);
}

int last = numberLine.getLast();
int first = numberLine.getFirst();
int max = Collections.max(numberLine);
int min = Collections.min(numberLine);

Answer 2

如果可能的话，我总是喜欢将特殊情况从循环中取出。这绝对有可能：

// variables
Random generator = new Random();
int max = 0, min = 100, random, first, last;

public FirstAndLast() {
    // for
    System.out.println("Here are 10 random numbers: \n");
    first = nextRandomNumber();
    for (int count = 2; count <= 9; count++) {
        nextRandomNumber();
    }
    last = nextRandomNumber();

    // output
    System.out.print("\n\nThe first number is " + first);
    System.out.print("\nThe last number is " + last);
    System.out.println("\nThe largest random number is " + max);
    System.out.println("The smallest random number is " + min);
}

private int nextRandomNumber() {
    // get random number and output
    random = 1 + generator.nextInt(100);
    System.out.print(random + " ");

    // Max number
    if (random > max)
        max = random;

    // Min number
    if (random < min)
        min = random;

    return random;
}

我介绍了一种辅助方法来处理每个数字。

顺便说一下，您似乎在输出中交换了first和last。

Answer 3

import java.util.Random;

public class RandomGenerated {

    public static void main(String[] args) {
        // variables
        Random generator = new Random();
        int max = 0, min = 100, random, first = 0, last = 0;

        // for
        System.out.println("Here are 10 random numbers: \n");
        for (int count = 1; count <= 10; count++) {

            // get random number and output
            random = 1 + generator.nextInt(100);
            System.out.print(random + " ");

            // last
            if (count == 10) {
                last = random;
            }

            // first
            if (count == 1) {
                first = random;
            }

            // Max number
            if (random > max)
                max = random;

            // Min number
            if (random < min)
                min = random;
        }

        // output
        System.out.print("\n\nThe first number is " + first);
        System.out.print("\nThe last number is " + last);
        System.out.println("\nThe largest random number is " + max);
        System.out.print("The smallest random number is " + min);
    }

}

如何在随机生成的数字行中找到第一个和最后一个数字？

3 个答案: