Question

我有这个SQL查询，用于查找每个帐户每月的试算平衡移动。

/* Fixed Assets 1 */
SELECT * FROM
(
    SELECT T0.AcctCode AS 'SAP Code', T0.AcctName AS 'Description', 
    MONTH(T1.RefDate) AS Month, SUM(T1.Debit - T1.Credit) AS 'Amount'
    FROM OACT T0
    LEFT JOIN JDT1 T1 ON T0.[AcctCode] = T1.[Account] 
    WHERE T0.AcctCode LIKE '111%' AND T0.Levels = 5
    AND (T1.RefDate BETWEEN DATEADD(yy, DATEDIFF(yy,0,{?AsAtDate}), 0) AND {?AsAtDate}) 
    GROUP BY T0.AcctCode, T0.AcctName, T0.FatherNum, T1.RefDate) AS q
    PIVOT
(
SUM(Amount) 
FOR [Month] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12])
) AS query

这将从6月返回以下结果：

我想包含所有行的累计月结果 1结果应该是：

1, 111110, Building Gross Value, 633604.23, 637764.23, 645313.03, 649061.78, 651097.78, 651097.78, 651397.78

我没有成功实现这一目标。如何修改查询以实现此目的？

其他数据：

查询：

SELECT CAST(T0.TaxDate AS Date), T0.Account, T1.AcctName, T0.Debit, T0.Credit
FROM JDT1 T0 INNER JOIN OACT T1
ON T0.Account = T1.AcctCode
WHERE T0.[Account] = '111110'

返回：

Answer 1

您需要在外部选择中将列添加到另一个：

SELECT AcctCode AS 'SAP Code', AcctName AS 'Description', 
col1 AS '1', 
col1 + col2 AS '2', 
col1 + col2 + col3 AS '3',
... FROM (
    SELECT AcctCode, AcctName, 
    [1] AS col1, 
    [2] AS col2, 
    [3] AS col3,
    ... FROM
    (
        SELECT T0.AcctCode, T0.AcctName, 
        MONTH(T1.RefDate) AS Month, SUM(T1.Debit - T1.Credit) AS 'Amount'
        FROM OACT T0
        LEFT JOIN JDT1 T1 ON T0.[AcctCode] = T1.[Account] 
        WHERE T0.AcctCode LIKE '111%' AND T0.Levels = 5
        AND (T1.RefDate BETWEEN DATEADD(yy, DATEDIFF(yy,0,{?AsAtDate}), 0) AND {?AsAtDate}) 
        GROUP BY T0.AcctCode, T0.AcctName, T0.FatherNum, T1.RefDate) AS q
        PIVOT
    (
    SUM(Amount) 
   FOR [Month] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12])
    ) AS query
)

Answer 2

最直接的方法是将数据结果转储到临时表中，或者，如果数据集相当小，则转储表变量。然后使用UNION从PIVOT获取累积结果和子类别。以下是使用表变量的示例。

/* Fixed Assets 1 */
SELECT * 
INTO #FixedAssets FROM
(
    SELECT T0.AcctCode AS 'SAP Code', T0.AcctName AS 'Description', 
    MONTH(T1.RefDate) AS Month, SUM(T1.Debit - T1.Credit) AS 'Amount'
    FROM OACT T0
    LEFT JOIN JDT1 T1 ON T0.[AcctCode] = T1.[Account] 
    WHERE T0.AcctCode LIKE '111%' AND T0.Levels = 5
    AND (T1.RefDate BETWEEN DATEADD(yy, DATEDIFF(yy,0,{?AsAtDate}), 0) AND {?AsAtDate}) 
    GROUP BY T0.AcctCode, T0.AcctName, T0.FatherNum, T1.RefDate) AS q
    PIVOT
(
SUM(Amount) 
FOR [Month] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12])
) AS query
GO

SELECT 
      [SAP Code]    = '111110' 
    , [Description] = 'Building Gross Value'
    , [1]           = SUM([1])
    , [2]           = SUM([2])
    , [3]           = SUM([3])
    , [4]           = SUM([4])
    , [5]           = SUM([5])
    , [6]           = SUM([6])
    , [7]           = SUM([7])
    , [8]           = SUM([8])
    , [9]           = SUM([9])
    , [10]          = SUM([10])
    , [11]          = SUM([11])
    , [12]          = SUM([12])
UNION
SELECT * FROM #FixedAssets
ORDER BY 1

Answer 3

如果我正确理解了您的问题，您需要在一行中使用逗号分隔的借记值

累积每月结果

create table a
(dateval date, acc int,accname varchar(100), debit decimal(10,2))

insert into a
values
('20150630', 111110, 'Building Gross Value', 633604.230),
('20150731', 111110, 'Building Gross Value', 2760.000000),
('20150730', 111110, 'Building Gross Value', 1400.000000),
('20150808', 111110, 'BUIIdlngGrossValue', 1890.00),
('20150811', 111110, 'BUIIdlnanossValue', 180.00),
('20150811', 111110, 'Building Gross Value', 375.000000),
('20150819', 111110, 'Building Gross Value', 2622.200000),
('20150821', 111110, 'Building Gross Value', 360.000000),
('20150822', 111110, 'Building Gross Value', 21.600000),
('20150824', 111110, 'Building Gross Value', 100.000000),
('20150825', 111110, 'Building Gross Value', 770.000000),
('20150829', 111110, 'Building Gross Value', 100.000000),
('20150831', 111110, 'Building Gross Value', 340.000000),
('20150831', 111110, 'Building Gross Value', 790.000000),
('20150924', 111110, 'Building Gross Value' ,918.750000),
('20150928', 111110, 'Building Gross Value', 2830.000000),
('20151005', 111110, 'Building Gross Value', 1411.000000),
('20151023', 111110, 'Building Gross Value', 625.000000)

现在，下面提到的查询将在一行中以逗号分隔值为您提供结果..

with cte as 
(
select * from
(
    select a.dateval,b.acc,b.accname,sum(b.debit) as debit,row_number() over (partition by year(a.dateval),month(a.dateval) order by a.dateval desc) as rn
    from (select distinct dateval from a) as a
    inner join a as b
    on a.dateval >= b.dateval
    group by a.dateval,b.acc,b.accname
) as a
where rn = 1
)
select acc,accname,stuff((select ',' + cast(debit as varchar(1000)) from cte as b where a.acc = b.acc for xml path ('')),1,1,'')
from cte as a
group by acc,accname

SQL - 返回累积每月列值

3 个答案: