我有以下课程
public class MyClass
{
[XmlElement("PersonList")]
public List<Data> DataList { get; set; }
}
// Rename this to 'Person'
public class Data
{
public string Name { get; set; }
}
我希望使用Xml seriPersonalize
Serializer
'MyClass',我想要关注输出xml
<?xml version="1.0" encoding="utf-8"?>
<MyData xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<PersonList>
<Person>
<Name>abc</Name>
</Person>
<Person>
<Name>pqr</Name>
</Person>
<Person>
<Name>xyz</Name>
</Person>
</PersonList>
</MyData>
请使用XmlElement
或XmlRoot
帮助获取此xml结构以重命名标记
答案 0 :(得分:0)
a = MAX AND b = MAX OR
a = NULL AND b = MAX OR
a = MAX AND b = NULL OR
a = NULL AND b = NULL
https://msdn.microsoft.com/en-us/library/system.xml.serialization.xmlrootattribute(v=vs.110).aspx
答案 1 :(得分:0)
我们可以使用
实现这一目标XmlArray
和
XmlArrayItem
public class MyClass
{
[XmlArray("PersonList")]
[XmlArrayItem("Person")]
public List<Data> DataList { get; set; }
}
public class Data
{
public string Name { get; set; }
}