我使用Laravels查询构建器检索带有一些过滤器选项的项目列表 - 我需要在此查询中进行计数:
$f = DB::table('Likes')
->join('Freestyle', 'Likes.FreestyleID', '=', 'Freestyle.id')
->join('Beat', 'Freestyle.BeatId', '=', 'Beat.id')
->join('Track', 'Beat.TrackId', '=', 'Track.id')
->join('Genre', 'Track.GenreId', '=', 'Genre.id')
->select('Likes.freestyleID as likeFreestyleID', 'Freestyle.*', 'Beat.TrackId as UseMeForTrack',
'Genre.id as GenreID')
->where('Freestyle.Active', '1')
->where('Freestyle.created_at', '>', "$dateScope")
->whereNull('Freestyle.deleted_at')
->whereIn('GenreID', $request->genre)
->first();
计算' FreestyleID'的次数。出现在喜欢的表格中。
这可能吗?返回的数据是完美的我只需要喜欢自由式的数量,其中like表中的FreestyleID为空。答案 0 :(得分:0)
这样的事情:
$f = DB::table('Likes')
->join('Freestyle', 'Likes.FreestyleID', '=', 'Freestyle.id')
->join('Beat', 'Freestyle.BeatId', '=', 'Beat.id')
->join('Track', 'Beat.TrackId', '=', 'Track.id')
->join('Genre', 'Track.GenreId', '=', 'Genre.id')
->select('Likes.freestyleID as likeFreestyleID','count(Likes.FreestyleID)', 'Freestyle.*', 'Beat.TrackId as UseMeForTrack',
'Genre.id as GenreID')
->where('Freestyle.Active', '1')
->where('Freestyle.created_at', '>', "$dateScope")
->whereNull('Freestyle.deleted_at')
->whereIn('GenreID', $request->genre)
->first();
答案 1 :(得分:0)
我认为你应该可以使用这样的raw expression
:
$f = DB::table('Likes')
->join('Freestyle', 'Likes.FreestyleID', '=', 'Freestyle.id')
->join('Beat', 'Freestyle.BeatId', '=', 'Beat.id')
->join('Track', 'Beat.TrackId', '=', 'Track.id')
->join('Genre', 'Track.GenreId', '=', 'Genre.id')
->select(DB::raw('COUNT(likes.FreestyleID) as num_likes'), 'Likes.freestyleID as likeFreestyleID', 'Freestyle.*', 'Beat.TrackId as UseMeForTrack',
'Genre.id as GenreID')
->where('Freestyle.Active', '1')
->where('Freestyle.created_at', '>', "$dateScope")
->whereNull('Freestyle.deleted_at')
->whereIn('GenreID', $request->genre)
->groupBy('Freestyle.id')
->first();