Question

我有两个数组如下：

包含项目结构的给定任务的工作时间。以及如下信息， [projectname] - 项目名称

[structurename] - 结构名称（项目有很多结构）

[taskname] - 任务名称（结构有很多任务）

[taskstartdate] - 任务的开始日期

[估计小时] - 估计任务的小时数

[小时] - 员工处理任务的小时数

[createdon] - 员工工作小时数的日期

Array ( [0] => stdClass Object ( [projectname] => test p1 [structurename] => test structure [taskname] => task [taskstartdate] => 2016-02-02 00:00:00 [estimatedhours] => 10.00 [hours] => 5.00 [createdon] => 2016-02-03 07:38:08 )
        [1] => stdClass Object ( [projectname] => test p1 [structurename] => test structure [taskname] => task [taskstartdate] => 2016-02-02 00:00:00 [estimatedhours] => 10.00 [hours] => 2.00 [createdon] => 2016-02-04 14:21:34 )
        [2] => stdClass Object ( [projectname] => p2 [structurename] => struc [taskname] => p2t1 [taskstartdate] => 2016-02-03 00:00:00 [estimatedhours] => 8.00 [hours] => 2.00 [createdon] => 2016-02-04 11:05:31 )
        [3] => stdClass Object ( [projectname] => p2 [structurename] => struc [taskname] => p2t1 [taskstartdate] => 2016-02-03 00:00:00 [estimatedhours] => 8.00 [hours] => 6.00 [createdon] => 2016-02-05 08:00:22 )
        [4] => stdClass Object ( [projectname] => web dev [structurename] => dev test [taskname] => dev task [taskstartdate] => 2016-02-04 00:00:00 [estimatedhours] => 30.00 [hours] => 8.00 [createdon] => 2016-02-04 08:21:14 ))

第二个数组包含给定周的天数（在本例中为2016年第一周，2月）

Array ( [0] => 2016-02-01
        [1] => 2016-02-02
        [2] => 2016-02-03
        [3] => 2016-02-04
        [4] => 2016-02-05 )

使用上述两个数组我想创建一个单个数组对象，如下所示，这背后的想法是为一个项目创建一行数组，并为给定的05天添加工作小时数。预期数组的描述如下，

[name] - [projectname] |的组合[structurename] |第一个数组的[taskname]

[taskstartdate] - 第一个数组的任务开始日期

[估计小时] - 从第一个阵列估计的小时数

[01] - 从2016-02-01获取01并从第二个数组

[02] - 从2016-02-02获得02并从第二个数组

[03] =＆gt; 5.00 - 从2016-02-03获得03并从第二个阵列添加为关键字并且还添加5.00作为值。

这是因为第一个数组[hours] =＆gt; 5.00 [createdon] =＆gt; 2016-02-03 07:38:08这意味着一名员工在2016-02-03工作了5个小时，所以应该将其作为价值添加。

[04] =＆gt; 2.00 - 根据[1] =＆gt; stdClass第一个数组员工的对象在2016-02-04

 Array ( [0] => stdClass Object ( [name] => test p1 | test structure | task [taskstartdate] => 2016-02-02 00:00:00 [estimatedhours] => 10.00    [01] => 0 [02] => 0 [03] => 5.00 [04] => 2.00 [05] => 0)
         [1] => stdClass Object ( [name] => p2 | struc | p2t1               [taskstartdate] => 2016-02-03 00:00:00 [estimatedhours] => 8.00     [01] => 0 [02] => 0 [03] => 0 [04] => 2.00 [05] => 6.00 )
         [2] => stdClass Object ( [name] => web dev | dev test | dev task   [taskstartdate] => 2016-02-04 00:00:00 [estimatedhours] => 30.00    [01] => 0 [02] => 0 [03] => 0 [04] => 8.00 [05] => 6.00)

我希望您能理解逻辑，如果需要更多信息，请发表评论。

这超出了我的理解，所以我没有为此尝试代码。

最好的问候。

PHP：如何创建stdClass数组，并排序另一个02数组

0 个答案: