Question

我有一个返回所有claim_id的ajax。从claim_id开始，我调用另一个ajax来获取此claim_id的所有字段。但我无法将第一个ajax中claim_id的值传递给内部ajax中的success函数。它将始终返回claim_id的最后一个值。我怎样才能分别得到claim_id？

$(document).ready( function () {

    var c_id = document.getElementById("c_id").value;

    $.ajax({
           url: '../rest/CategoryService/compcategory/'+c_id,
           type: 'POST',
           data: {
              format: 'json'
           },
           error: function() {
              $('#info').html('<p>An error has occurred</p>');
           },
           success: function(data) {

               //get the claim id
                for (i in data){            

                    var claim_id = data[i].iD;
                    // alert(claim_id); 

                    //get all the fields for the claim id
                    $.ajax({
                           url: '../rest/CategoryService/fieldcategory/'+claim_id,
                           type: 'POST',
                           data: {
                              format: 'json'
                           },
                           error: function() {
                              $('#info').html('<p>An error has occurred</p>');
                           },
                           success: function(data2) {

                               var textfield = "";
                               //construct the header fields                       
                               textfield += "<th>Sub Category</th>";

                               for (z in data2){    

                                   var field = data2[z].field;

                                   textfield += "<th>"+field+"</th>";

                               }

                               textfield += "<th>Action</th>";
                               alert(claim_id); 
                               alert(textfield);        

                                $("#tabledata"+claim_id+" thead").append(
                                "<tr>"+textfield+"</tr>");

                           },

                        });
                }
           },

        });

} );

Answer 1

您可以在第二个ajax params中定义它，然后在成功函数中使用this.param_name

var claim_id = data[i].iD;

$.ajax({
    url: '../rest/CategoryService/fieldcategory/'+claim_id,
    claim_id: claim_id,  // defining your custome params here
    /*your other params*/
    success: function(data2) {

        alert(this.claim_id); // will alert your var claim_id variable
    }
});

或第二个选项选项是在js中定义全局变量并成功使用

Answer 2

基本上你的代码中的问题是for循环不会等待ajax调用完成。这就是你永远获得最后claim_id的原因。请尝试以下代码：

$(document).ready( function () {

        var c_id = document.getElementById("c_id").value;

        $.ajax({
               url: '../rest/CategoryService/compcategory/'+c_id,
               type: 'POST',
               data: {
                  format: 'json'
               },
               error: function() {
                  $('#info').html('<p>An error has occurred</p>');
               },
               success: function(data) {

                    var getClaimData = function(pointer, dataLength) {
                        var claim_id = data[pointer].iD;

                        $.ajax({
                               url: '../rest/CategoryService/fieldcategory/'+claim_id,
                               type: 'POST',
                               data: {
                                  format: 'json'
                               },
                               error: function() {
                                  $('#info').html('<p>An error has occurred</p>');
                               },
                               success: function(data2) {

                                   var textfield = "";
                                   //construct the header fields                       
                                   textfield += "<th>Sub Category</th>";

                                   for (z in data2){    

                                       var field = data2[z].field;

                                       textfield += "<th>"+field+"</th>";

                                   }

                                   textfield += "<th>Action</th>";
                                   alert(claim_id); 
                                   alert(textfield);        

                                    $("#tabledata"+claim_id+" thead").append(
                                    "<tr>"+textfield+"</tr>");

                                    pointer++;
                                    if(pointer < dataLength) {
                                        getClaimData(pointer, dataLength);
                                    }

                               },

                            });
                    };

                    getClaimData(0, data.length);
               },

            });

    });

如何将js变量从ajax传递到内部ajax？

2 个答案: