我需要一个help.i需要使用Angular.js在ng-options对象中使用两个索引(i.e-$index,$parent.$index
)。我正在解释下面的代码。
<tr ng-repeat="d in days">
<td>{{d.day_name}}</td>
<td>
<table>
<tbody>
<tr ng-repeat="answer in d.answers">
<td>
<select class="form-control" id="answer_{{$index}}_{{$parent.$index}}_category" name="answer_{{$index}}_category" ng-model="answer.catagory" ng-options="cat.name for cat in listOfCatagory track by cat.value" ng-change="removeBorder($index,answer.catagory.value,$parent.$index);">
<option value="">Select Category</option>
</select>
</td>
</tr>
</tbody>
</table>
</td>
<td>
<table>
<tbody>
<tr ng-repeat="answer in d.answers">
<td>
<select class="form-control" id="answer_{{$index}}_{{$parent.$index}}_subcategory" name="answer_{{$index}}_subcategory" ng-model="answer.subcatagory" ng-options="sub.name for sub in listOfSubCatagory[$index+$parent.$index] track by sub.value">
<option value="">Select Subcategory</option>
</select>
</td>
</tr>
</tbody>
</table>
</td>
<td>
<table>
<tbody>
<tr ng-repeat="answer in d.answers">
<td>
<input type="text" id="answer_{{$index}}_{{$parent.$index}}_comment" name="answer_{{$index}}_comment" placeholder="Add Comment" ng-model="answers.comment">
</td>
</tr>
</tbody>
</table>
</td>
<td>
<table>
<tbody>
<tr ng-repeat="answer in d.answers">
<td>
<input type="submit" name="plus" id="plus" value="+" style="width:20px; text-align:center;" ng-click="addNewRow(d.answers, true)">
<div ng-show="$first && !$last">
<input type="submit" name="minus" id="minus" value="-" style="width:20px; text-align:center;" ng-click="removeRow(d.answers, $last)">
</div>
</td>
</tr>
这里我需要传递两个带listOfSubCatagory
的索引,以便我可以动态设置多维数据。我做了一些coading,但它没有按要求工作。我正在解释下面的控制器端代码。
$scope.listOfSubCatagory = [];
$scope.removeBorder=function(index,catvalue,parent){
console.log('ind',index,catvalue,parent);
$scope.listOfSubCatagory[index+parent]=[];
var catdata=$.param({'action':'subcat','cat_id':catvalue});
$http({
method:'POST',
url:"php/customerInfo.php",
data:catdata,
headers: { 'Content-Type': 'application/x-www-form-urlencoded' }
}).then(function successCallback(response){
angular.forEach(response.data,function(obj){
var data={'name':obj.subcat_name,'value':obj.subcat_id};
$scope.listOfSubCatagory[index+parent].push(data);
})
},function errorCallback(response) {
})
}
$scope.days=[];
$http({
method:'GET',
url:"php/customerInfo.php?action=day",
headers: { 'Content-Type': 'application/x-www-form-urlencoded' }
}).then(function successCallback(response){
//console.log('day',response.data);
angular.forEach(response.data, function(obj) {
obj.answers = [];
$scope.addNewRow(obj.answers);
$scope.days.push(obj);
});
},function errorCallback(response) {
})
}
$scope.addNewRow = function(answers, hasDelete) {
answers.push({
category: null,
subcategory: null,
comment: null,
hasDelete: hasDelete ? hasDelete : false
});
};
$scope.removeRow = function(answers, $index){
answers.splice($index, 1);
};
请帮我解决此问题。
答案 0 :(得分:0)
我已经为您更新了我的plunker代码。如果您使用类似方法,那么您可能会得到所需的结果。
对不起早期plunk
的拼写错误。我现在改进了它们。
您可以相应地更新代码,