Question

我有一个包含几句话的SENTENCE1数组：

String[] SENTENCE1 = new String[]{
"This book is nice",
"I like it",
"I read them alot", 
"My favourite book", 
"I put it in a shelf"};

接下来，我还有一个从SENTENCE1数组中随机获得的句子数组，称为SENTENCE2：

String[] SENTENCE2 = new String[]{
"I put it in a shelf" ,   
"I like it",
"My favourite book"};

如何根据SENTENCE1中的外观顺序对SENTENCE2数组进行排序，以便SENTENCE2中的输出为：

I like it
My favourite book
I put it in a shelf

无论如何，我试图这样做并循环遍历它们，但它显示Arrays不受限制。

for (int g=0;g<SENTENCE2.length;g++){
    for (int o=0;o<SENTENCE1.length;o++)
    {
        if (SENTENCE2[g].contains(SENTENCE1[o])){
            System.out.println(SENTENCE2[g])
        }
    }
}

感谢您的帮助。

Answer 1

您的代码是正确的，如果要完成String的完全匹配，有一点是您不需要contains。使用equals

for(int i = 0; i < sent1.length; i++){
    for(int j = 0; j < sent2.length; j++){
        if(sent1[i].equals(sent2[j])){
            System.out.println(sent2[j]);
        }
    }
}

始终在java中使用camel大小写用于局部变量

Answer 2

试试这个。

inspect.getdoc(object)
inspect.getcomments(object)
inspect.getfile(object) 
inspect.getmodule(object)

Answer 3

 TreeMap<Integer, String> map = new TreeMap<>();

 for (int i=0;i<SENTENCE2.length;i++) {
     for (int j = 0; j < SENTENCE1.length; j++) {
         if (SENTENCE2[i].equals(SENTENCE1[j])) {
             map.put(j, SENTENCE2[i]);
         }
     }
 }

 map.values().toArray(SENTENCE2);

 for(String value: SENTENCE2){
     System.out.println(value);
 }

在TreeMap中，值将自动按键排序。

Answer 4

如果您乐意使用google guava之类的外部库。它可以很容易地完成如下：

public static void main(String[] args) {
    String[] SENTENCE1 = new String[]{
        "This book is nice",
        "I like it",
        "I read them alot",
        "My favourite book",
        "I put it in a shelf"};

    String[] SENTENCE2 = new String[]{
        "I put it in a shelf",
        "I like it",
        "My favourite book"};

    Comparator<String> SENTENCE1_COMPARATOR = Ordering.explicit(Arrays.asList(SENTENCE1));
    Arrays.sort(SENTENCE2, SENTENCE1_COMPARATOR);
    System.out.println(Arrays.toString(SENTENCE2));
}

Answer 5

你可以这样做：

    @Test
public void test() {
    String[] SENTENCE1 = new String[]{
            "This book is nice",
            "I like it",
            "I read them alot",
            "My favourite book",
            "I put it in a shelf"};
    String[] SENTENCE2 = new String[]{
            "I put it in a shelf",
            "I like it",
            "My favourite book"};


    System.out.println(SENTENCE1.length);
    for(int i= 0 ;i<SENTENCE1.length;i++){
        boolean flag = false;
        for(int j = 0; j<SENTENCE2.length;j++){
            if(SENTENCE2[j].equals(SENTENCE1[i])){
                flag = true;
                break;
            }
        }
        if(!flag){
            SENTENCE1[i]=null;
        }
    }

    for(int k=0;k<SENTENCE1.length;k++){
        if(SENTENCE1[k]!=null)
            System.out.println(SENTENCE1[k]);
    }
}

根据原始句子数组对句子数组进行排序

5 个答案: