Question

如何从jQuery调用PHP函数

getstudent('"+$("#classroom").val()+"')

我确定MySQL有4条关于classroomid='c1'

的记录

但我无法向选择框学生显示4条记录

在HTML中

<select  name="classroom" id="classroom" class="required"><option value="c1" selected>Room-1</option><option value="c2">Room-2</option></select>

在jQuery中

$("#selectstudent").append("<tr><td><select name='student["+x+"]' id='student"+x+"'><?=getstudent('"+$("#classroom").val()+"')?></select>")</td></tr>").trigger('create');

在PHP中

function getstudent($roomid){
  $query = "Select studentid,studentname From student Where classroomid='$roomid' Order By studentid";
  $sql=mysql_query($query);
  if (mysql_num_rows($sql)){
    while ($rs = mysql_fetch_assoc($sql)){
      $str = $str."<option value='".$rs["studentid"]."'>".$rs["studentname"]."</option>";
    }
  }else{
    $str="";
  }
  //test//
  $str = $str."<option value=''>".$query."</option>";
  $str = $str."<option value=''>".mysql_num_rows($sql)."</option>";
  return $str;
}

我只得到＆＃34; Select studentid,studentname From student Where classroomid='c1' Order By studentid＆＃34;并且＆＃34; 0＆＃34;在选择框学生

如果我删除＆＃34; Where classroomid='$roomid'＆＃34;来自$ query，它可以将所有数据显示到selectbox student

中

我粘贴＆＃34; Select studentid,studentname From student Where classroomid='c1' Order By studentid＆＃34;查询phpMyAdmin的窗口并运行，它显示4条记录

jQuery动态追加SelectBOX来调用PHP的mysql函数

0 个答案: