无法从IntentService更新UI

时间:2016-03-17 20:30:14

标签: android android-intentservice localbroadcastmanager

看似简单的要求 - 从IntentService更新UI。在下面的镜头中,当点击Start Service按钮时,我需要在唯一ProgressBar上方显示TextView,并在延迟后删除ProgressBar

AVD Screenshot

在SO上找到了很多答案,但不知何故仍无法破解它。我从this了解LocalBroadcastManager是一个很好的方法。我也尝试过关注this,(使用Handler s的方法),但它也无法显示ProgressBar。最后,根据this回答,这是我最终得到的结果。在完成所有日志记录之后,到目前为止我管理的输出只是连续出现的Toast

非常感谢你能指出我出错的地方,现在已经挣扎了很长时间。非常感谢提前!

MainActivity已更新

public class MainActivity extends AppCompatActivity
{
    private static final String TAG = "MainActivity";
    private ProgressBar pb;
    private MyBroadcastReceiver myBroadcastReceiver;

    @Override
    protected void onCreate(Bundle savedInstanceState)
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        pb = (ProgressBar) findViewById(R.id.pb);
        myBroadcastReceiver = new MyBroadcastReceiver();

        LocalBroadcastManager.getInstance(this).registerReceiver(myBroadcastReceiver, new IntentFilter("ACTION"));
    }

    private void updateUI(boolean show)
    {
        if (show)
            pb.setVisibility(View.VISIBLE);
        else
            pb.setVisibility(View.GONE);
//        Toast.makeText(this, "UI Updated...", Toast.LENGTH_LONG).show();
    }

    public void startIt(View view)
    {
        Intent intent = new Intent(this, NanisIntentService.class);
        startService(intent);
    }

    public class MyBroadcastReceiver extends BroadcastReceiver
    {
        @Override
        public void onReceive(final Context context, Intent intent)
        {
            String action = intent.getAction();
            Log.e(TAG, "In onReceive(): " + action);
            if (action.equals("ACTION"))
            {
                updateUI(true);
            } // of if (action = "ACTION")
            else if (action.equals("NOITCA"))
            {
                updateUI(false);
            } // of else of if (action = "ACTION")
        } // of onReceive()
    } // of class MyBroadcastReceiver
}

IntentService已更新

public class NanisIntentService extends IntentService
{
    private static final String TAG = "NanisIntentService";

    public NanisIntentService()
    {
        super("NanisIntentService");
    }

    @Override
    protected void onHandleIntent(Intent intent)
    {
        Log.e(TAG, "In onHandleIntent(): Intent is being serviced");
        LocalBroadcastManager.getInstance(testing.com.myintentservice.NanisIntentService.this).sendBroadcast(new Intent().setAction("ACTION"));
        int i = 0;
        while (i <= 50)
        {
            try
            {
                Thread.sleep(50);
                i++;
                Log.e("", "" + i);
            } catch (InterruptedException e)
            {
                e.printStackTrace();
            }
        }
    }

    @Override
    public void onDestroy()
    {
        super.onDestroy();
        LocalBroadcastManager.getInstance(testing.com.myintentservice.NanisIntentService.this).sendBroadcast(new Intent().setAction("NOITCA"));
        Log.e(TAG, "In onDestroy(): The service has been destroyed");
    }
}

    @Override
    public void onStart(Intent intent, int startId)
    {
        super.onStart(intent, startId);
        LocalBroadcastManager.getInstance(testing.com.myintentservice.NanisIntentService.this).sendBroadcast(new Intent().setAction("ACTION"));
    }

    @Override
    public void onDestroy()
    {
        super.onDestroy();
        LocalBroadcastManager.getInstance(testing.com.myintentservice.NanisIntentService.this).sendBroadcast(new Intent().setAction("NOITCA"));
        Log.e(TAG, "In onDestroy(): The service has been destroyed");
    }
}

    @Override
    public void onDestroy()
    {
        super.onDestroy();
        LocalBroadcastManager.getInstance(testing.com.myintentservice.NanisIntentService.this).sendBroadcast(new Intent().setAction("NOITCA"));
        Log.e(TAG, "In onDestroy(): The service has been destroyed");
    }
}

activity_main.xml

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout
    xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:paddingBottom="@dimen/activity_vertical_margin"
    android:paddingLeft="@dimen/activity_horizontal_margin"
    android:paddingRight="@dimen/activity_horizontal_margin"
    android:paddingTop="@dimen/activity_vertical_margin"
    tools:context="testing.com.myintentservice.MainActivity">

    <ProgressBar
        android:id="@+id/pb"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_above="@+id/tv"
        android:layout_centerHorizontal="true"
        android:indeterminate="true"
        android:visibility="gone"/>

    <TextView
        android:id="@+id/tv"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_centerInParent="true"
        android:text="Hello IntentService!"
        android:textColor="#1298CE"
        android:textSize="32sp"/>

    <Button
        android:id="@+id/bt"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_alignParentBottom="true"
        android:layout_centerHorizontal="true"
        android:text="Start Service"
        android:onClick="startIt"/>
</RelativeLayout>

AndroidManifest

    <application
        android:allowBackup="true"
        android:icon="@mipmap/ic_launcher"
        android:label="@string/app_name"
        android:supportsRtl="true"
        android:theme="@style/AppTheme">
        <activity android:name=".MainActivity">
            <intent-filter>
                <action android:name="android.intent.action.MAIN"/>

                <category android:name="android.intent.category.LAUNCHER"/>
            </intent-filter>
        </activity>
        <service android:name="testing.com.myintentservice.NanisIntentService"/>
    </application>

2 个答案:

答案 0 :(得分:2)

首先,你将主应用程序线程绑定~2.5秒。这将在这段时间内冻结您的UI。 不要这样做

其次,你在~2.5秒之前调用updateUI()一次,之后调用一次。由于您在此期间绑定了主应用程序线程,因此在延迟后连续两次调用updateUI()具有相同的视觉效果。 updateUI()切换ProgressBar种可见性,因此两次调用将相互取消,使您处于与开始时相同的状态。

  

我需要在唯一的TextView上方显示ProgressBar,并在延迟之后删除ProgressBar。

显示ProgressBar 2.5秒,无论是否进行任何实际工作,都是相当随意的。

话虽如此,请拨打updateUI()一次,然后使用pb.postDelayed()安排Runnable在2500毫秒后运行run()方法Runnable }第二次调用updateUI()。这可以避免阻止主应用程序线程,因此它允许第一个updateUI()调用生效,同时仍然为您提供2.5秒的持续时间。

答案 1 :(得分:0)

非常感谢,@ CommonsWare!终于搞定了。对于两个不同的操作,它需要两个接收器,我发现here

为了那些寻找最终工作代码的人的利益......

结果屏幕:点击后,处理后

请原谅代码中的任何复制粘贴鬼,它毕竟是PoC,虽然功能正常。