Question

我有一个用于传递SOAP命令的泛型函数。我需要查看发送的RAW XML数据到服务器以诊断错误。我该怎么做？

Answer 1

没关系，这似乎非常接近点！

http://www.scottnichol.com/nusoapintro.htm

echo '<h2>Request</h2>';
echo '<pre>' . htmlspecialchars($client->request, ENT_QUOTES) . '</pre>';
echo '<h2>Response</h2>';
echo '<pre>' . htmlspecialchars($client->response, ENT_QUOTES) . '</pre>';

// Display the debug messages
echo '<h2>Debug</h2>';
echo '<pre>' . htmlspecialchars($client->debug_str, ENT_QUOTES) . '</pre>';

Answer 2

虽然这是一篇旧帖子，但我想用我自己的tzmatt答案填写。

class soapBug {

    /*
     * @var obj $debug client object
     * @var string $what Just a name for the header so you know
     * what you are looking at.
     */
    public function bug($debug, $what) {
        /* ive stayed with the original here, but you could look at
         * http://www.php.net/manual/en/tidy.repairstring.php to
         * output in clean xml.
         *
         * I just grab the line i need and paste
         * it into my IDE and let it format for me, works just as well
         * and no coding to fiddle with for something that wont be
         * permanent on my project.
         */
        echo '<h2>' . $what . '</h2>';
        echo '<pre>' . htmlspecialchars($debug, ENT_QUOTES) . '</pre>';

    }

}

class someClass {

    private $de;
    // private to this class to prevent accidental call
    // outside the class.

    public function __construct() {

           $this->de = new soapBug;
    }

    public function thatNeedsDebugging() {

        /* 
         * Simple enough to debug your client now no need to copy
         * the html block all over you can debug with just one line
         * of call all of them
         */
        $this->de->bug($client->request, 'Request'); // I grab this output string
        $this->de->bug($client->response, 'Response');
        $this->de->bug($client->debug_str, 'Debug');
    }
}

如何查看nusoap的“原始xml”输出？

2 个答案: