极坐标图以磁性局部时间（0-23）为方位角，以磁纬度（90-0）为半径

Question

我一直在尝试使用pypthon中的matplotlib绘制极坐标图但有一些问题。而不是正常的0-360度，我想把时间，0-23小时和半径将是纬度，即从90-0（极点到赤道）。

我试图在matplotlib投影polar.py示例中更改一些设置，但结果并没有不同。这就是我得到的：

Answer 1

如果您小心，可以考虑反转纬度并手动更改两个轴上的刻度标签。

以下是如何实现这一目标的示例，更多解释为评论：

$app->cache->put($requestCache . '_Minute', 0, 1); // value 0, expire in 1 minute
$app->cache->increment($requestCache . '_Minute'); // doing this resets the 1 minute expire time

您的结果将如下所示（请记住随机数据会有所不同）：

要确定它确实有效，您可以使用以下行替换随机import numpy as np from matplotlib import pyplot as plt # set up random data between 0 and 90 r = [np.random.random() * 90.0 for i in range(0,10)] # set up 24 hours matching the random data above hours = np.linspace(0.0,24.0,len(r)) # scaling the 24 hours to the full circle, 2pi theta = hours / 24.0 * (2.0 * np.pi) # reverse your data, so that 90 becomes 0: r_rev = [(ri - 90.0) * -1.0 for ri in r] # set up your polar plot ax = plt.subplot(111, projection='polar') ax.plot(theta, r_rev, color='r', linewidth=3) # define your axis limits ax.set_ylim([0.0, 90.0]) # statically reverse your y-tick-labels # caution: this turns your labels into strings # and decouples them from the data # # the np.linspace gives you a distribution between 90 and 0 - # the number of increments are related to the number of ticks # however, you require one more label, because the center is # omitted. ax.set_yticklabels(['{:.0f}'.format(ylabel) \ for ylabel in np.linspace(90.0,0.0,len(ax.get_yticklabels())+1)[1:]]) # statically turn your x-tick-labels into fractions of 24 # caution: this turns your labels into strings # and decouples them from the data # # the number of ticks around the polar plot is used to derive # the appropriate increment for the 24 hours ax.set_xticklabels(['{:.1f}'.format(xlabel) \ for xlabel in np.arange(0.0,24.0,(24.0 / len(ax.get_xticklabels())))]) ax.grid(True) plt.show() ：

r

现在你知道了r = np.linspace(0,90,10) - 值，并且可以看到它们是如何被翻转的。