Question

if Class.lower() == ("classa"):
    from collections import defaultdict #Automatically creates an empty list
    scores = defaultdict(list)#Creates the variable called scores


    with open('ClassA.txt') as f:#Opens the text file for classA
            for score, name in zip(f, f):#Makes the users 
                    scores[name.strip()].append(int(score))#Appends scores to a list as you cant have the same key twice in a dictionary.

文本文件如下所示： 10 穆罕默德 8 穆罕默德 9 穆罕默德五短发 4 短发 7 短发 3 迈克尔 2 迈克尔五迈克尔 8 詹姆士 6 詹姆士 7 詹姆士 6 托尼 4 托尼 7 托尼 4 萨拉 6 萨拉 6 我希望能够从三个分数打印用户最高分然后我想打印用户分数从最高到最低，例如穆罕默德，因为他得到10分然后最后我还要打印用户分数从最高到最低的平均值。

Answer 1

如果我理解正确，这应该回答你的问题。

import re
for score, name in re.findall("(\d+) (\w+)", f.read()):  # using regular expressions module to parse the scores and names
    scores[name.strip()].append(int(score))

# Set highest scores first in list and print those sorted
# sort the individual scores high to low, list format[(name, scores),...,]
score_list = [(name, sorted(scores[name], reverse=True)) for name in scores]
# sort the named scores high to low by highest score(x[0] sorts names alphabetic)
score_list = sorted(score_list, key=lambda x: x[1], reverse=True)
print("Highest sorted")
for name, v in score_list:  # v contains the individual scores
    print(v[0], name)  # Print highest score which is at 0 index and print the name

print()
print("highest to lowest")
for name, v in score_list:  # v contains the individual scores
    print(v, name)  # Print scores and name

print()
print("highest average")
average_scores = []
# iterate through the ordered score list and append the average score to the average_scores list
for name, v in score_list:  # v contains the individual scores
    average_scores.append((name, sum(v) / len(v)))
# sort average_scores high to low
sorted_average_scores = sorted(average_scores, key=lambda x: x[1], reverse=True)
# iterate through sorted_average_scores and print the rounded average, non-sorted individual scores, and name
for name, average in sorted_average_scores:
    print(round(average), scores[name], name)

输出：

Highest sorted
10 Mohammad
8 James
7 Tony
7 Bob
6 Sara
5 Micheal

highest to lowest
[10, 9, 8] Mohammad
[8, 7, 6] James
[7, 6, 4] Tony
[7, 5, 4] Bob
[6, 4] Sara
[5, 3, 2] Micheal

highest average
9 [10, 8, 9] Mohammad
7 [8, 6, 7] James
6 [6, 4, 7] Tony
5 [5, 4, 7] Bob
5 [4, 6] Sara
3 [3, 2, 5] Micheal

按字母顺序从连接用户名和最高分的文本文件中对名称和分数进行排序

1 个答案: