Question

我是使用过滤器的新手，但我很想制作我正在构建可扩展的插件。

在我的主插件中，我有以下类和函数：

class Skizzar_Admin_Theme_Pages {

// Return (array) the properties of all Skizzar Admin Theme admin pages
static function get_pages( $page_slug = '' ) {

    $pages = array();
    // Default page properties
    $default_args = array(
        'menu-title' => '',
        'tab-title' => '',
        'parent' => 'admin.php',
        'in-menu' => false,
        'has-tab' => true,
        'tab-side' => false,
        'top-level' => false,
    );

    $pages['sat-options-general'] = array_merge(
        $default_args,
        array(
            'slug' => 'sat-options-general',
            'menu-title' => _x( 'Admin Theme', 'Page title in the menu', 'skizzar_admin_theme' ),
            'tab-title' => _x( 'Admin Theme Options', 'Option tab title', 'skizzar_admin_theme' ),
            'title' => _x( 'Admin Theme Options', 'Option page title', 'skizzar_admin_theme' ),
            'callback' => array( __CLASS__, 'display_general_options_page' ),
            'in-menu' => true,
            'top-level' => true,
        )
    );

    $pages['sat-addons'] = array_merge(
        $default_args,
        array(
            'slug' => 'sat-addons',
            'menu-title' => _x( 'Addons', 'Page title in the menu', 'skizzar_admin_theme' ),
            'tab-title' => _x( 'Addons', 'Option tab title', 'skizzar_admin_theme' ),
            'title' => _x( 'Browse Addons', 'Option page title', 'skizzar_admin_theme' ),
            'callback' => array( __CLASS__, 'display_addons_page' ),
            'in-menu' => true,
        )
    );



    return apply_filters( 'skizzar_admin_theme_tab', $pages, $default_args, $page_slug ); 

}

// Output the content of the requested options page
static function display_general_options_page() {
    $page_info = self::get_pages( 'sat-options-general' );
    include( plugin_dir_path( __FILE__ ) . 'inc/page-options-general.php' );
}
...
}

简而言之，此数组用于在该页面的顶部创建子菜单页面和选项卡等。你会看到我添加了过滤器：

apply_filters( 'skizzar_admin_theme_tab', $pages, $default_args, $page_slug );

对于函数get_pages()，这是我可以从插件添加页面。

在我的插件中，我有以下功能：

function add_google_analytics_tab( $pages, $default_args, $page_slug ) {

    $pages['sat-ga'] = array_merge(
            $default_args,
            array(
                'slug' => 'sat-ga',
                'menu-title' => _x( 'GA', 'Page title in the menu', 'skizzar_admin_theme' ),
                'tab-title' => _x( 'GA', 'Option tab title', 'skizzar_admin_theme' ),
                'title' => _x( 'GA', 'Option page title', 'skizzar_admin_theme' ),
                'callback' => array( __CLASS__, 'display_ga_page' ),
                'in-menu' => true,
            )
        );
        // Return
        if ( $page_slug ) {
            if ( ! isset( $pages[ $page_slug ] ) ) {
                return null;
            }
            return $pages[ $page_slug ];
        }
        return $pages;
}
function display_ga_page() {
    echo 'GA Settings Go Here';
}

然后使用以下add_filter函数调用它：

add_filter( 'skizzar_admin_theme_tab', array(&$this, 'add_google_analytics_tab', 1, 3) );

希望这会将数组添加到我的主插件中的get_pages()函数中，从而添加子菜单项和制表符等。

但是，我遇到了以下错误：

call_user_func_array() expects parameter 1 to be a valid callback, array must have exactly two members in ...plugin.php on line 235

Invalid argument supplied for foreach() in ...class-sat-menu.php on line 13

以下是class-sat-menu.php中引用的行

static function action_add_menu_entries() {

    // Skizzar Admin Theme pages
    foreach ( Skizzar_Admin_Theme_Pages::get_pages() as $page_info ) {

        if ( ! $page_info['in-menu'] ) {
            $page_info['parent'] = null;
        }

        if ($page_info['top-level']) {
            add_menu_page(
                $page_info['title'], // Page Title
                ( $page_info['menu-title'] ? $page_info['menu-title'] : $page_info['title'] ), // Menu Title
                Skizzar_Admin_Theme_User::get_admin_cap(), // Capability
                $page_info['slug'], // Slug
                $page_info['callback'] // Callback
            );

        }
        else {
            add_submenu_page(
                'sat-options-general',
                $page_info['title'],
                ( $page_info['menu-title'] ? $page_info['menu-title'] : $page_info['title'] ),
                Skizzar_Admin_Theme_User::get_admin_cap(),
                $page_info['slug'],
                $page_info['callback']
            );
        }

    }

}

我无法理解错误是什么，所以任何建议或帮助都会受到赞赏

Wordpress php问题与创建自定义筛选器

0 个答案: