执行以下代码时,它没有询问"允许" /"拒绝"选项(同意页面)。如果我使用gmail id登录,它将直接输入并显示用户信息。我不知道我想在此代码中做什么,以显示允许或拒绝谷歌同意页面。
如果我发表评论" $ client-> setHttpClient(new GuzzleHttp \ Client([' verify' => false]))"这段代码,致命错误:未捕获异常' GuzzleHttp \ Exception \ RequestException'消息' cURL错误60:SSL证书问题:无法获取本地颁发者证书错误被抛出。任何人都可以帮助我吗?
<?php
require_once __DIR__.'/google-api-php-client-master/vendor/autoload.php';
const CLIENT_ID='';
const CLIENT_SECRET='';
const REDIRECT_URI ='http://localhost:81/oauth/';
const SAMPLE_API_KEY='';
session_start();
$client=new Google_Client();
$client->setClientId(CLIENT_ID);
$client->setClientSecret(CLIENT_SECRET);
$client->setRedirectUri(REDIRECT_URI);
$client->setDeveloperKey(SAMPLE_API_KEY);
$client->addScope("https://www.googleapis.com/auth/userinfo.email");
$client->setHttpClient(new GuzzleHttp\Client(['verify'=>false]));
$plus=new Google_Service_Plus($client);
if(isset($_REQUEST['logout']))
{
session_unset();
unset($_SESSION['access_token']);
//$client->revokeToken($_SESSION['access_token']);
}
if(isset($_GET['code']))
{
$client->authenticate($_GET['code']);
$_SESSION['access_token']=$client->getAccessToken();
$redirect='http://'.$_SERVER['HTTP_HOST'].$_SERVER['PHP_SELF'];
header('Location:'.filter_var($redirect,FILTER_SANITIZE_URL));
}
if(isset($_SESSION['access_token'])&&$_SESSION['access_token'])
{
$client->setAccessToken($_SESSION['access_token']);
$me=$plus->people->get('me');
$id=$me['id'];
$name=$me['displayName'];
$email=$me['emails'][0]['value'];
$profile_image_url=$me['image']['url'];
$cover_image_url=$me['cover']['coverPhoto']['url'];
$profile_url=$me['url'];
}
else
{
$authUrl=$client->createAuthUrl();
}
?>
<div>
<?php
if(isset($authUrl)){
echo "<a href='".$authUrl."'><button>Login</button></a>";
}
else
{
print "Id: {$id} <br>";
print "Name : {$name} <br>";
print "Email : {$email} <br>";
echo "<a href='?logout'><button>Logout</button></a>";
}
?>
</div>