选择模型后,我的最佳模型有两个连续变量和一个交互项。
我的数据如下:
df<-structure(list(Height_RR = c(1.09861228866811, -0.143100843640673,
-0.990398704027877, -0.990398704027877, 0.0800427076735365, 0.916290731874155,
1.04982212449868, 0.430782916092454, 0.575364144903562, 0.0953101798043248,
-0.405465108108164, 0.132489183046079, 0.117783035656383, 1.04982212449868,
-0.916290731874155, 1.20397280432594, -0.356674943938732, 0.287682072451781,
-0.356674943938732, 0.287682072451781, -0.356674943938732, 0.287682072451781,
-0.318387168583869, -0.318387168583869, -0.318387168583869, -0.356674943938732,
-0.393042588109607, -0.485507815781701, -0.405465108108164, -0.441832752279039,
0.42744401482694, 0.510825623765991, 1.04982212449868, 0.847297860387204,
-0.356674943938732),
CWD = c(-173.850331373113, -1063.65743501896,
-1152.77456298827, -1200.14062275391, -1191.1454796875, -154.366681649412,
-160.237513231871, -148.917478721144, -655.155005728001, -1081.17124999999,
-192.437500000001, -664.538976252586, -540.755930464004, -230.945841787738,
-632.705104201392, -159.376784299775, -686.792144988283, -686.792144988283,
-686.792144988283, -686.792144988283, -686.792144988283, -686.792144988283,
-681.113600988285, -681.113600988285, -681.113600988285, -203.026923561875,
-32.6625046554887, -499.426709860029, -190.121159505859, -871.942483370128,
-988.569593505865, -248.140000031999, -165.422048285183, -165.422048285183,
-165.422048285183),
yi = c(0.201673327454905, 0.374187870755073,
-1.26459742614237, -3.4162352590267, -1.20397280432594, 0.943371690476826,
1.26291533995939, 0.551099522903931, 0.506212624114382, 1.62113395219729,
-0.272257602126149, 0.345151698858396, 0.104290175606367, 4.56284362374715,
0.532233017860013, 0.697137826765664, -1.01160091167848, -1.07044141170141,
0.646627164925052, -0.519875459285909, -0.646627164925052, -0.519875459285909,
-0.424883193965266, 0.074107972153722, 0.074107972153722, 0.693147180559945,
0.0707340508073709, 0.358554516423803, -0.682820066404096, -0.638455438611528,
0.410070448690588, 1.11317243999944, 1.26976054486394, 1.45111186119636,
1.44238382777093)), .Names = c("Height_RR", "CWD", "yi"), row.names = c(1L,
2L, 3L, 4L, 5L, 6L, 7L, 8L, 10L, 11L, 12L, 13L, 14L, 15L, 16L,
17L, 19L, 20L, 21L, 22L, 23L, 24L, 25L, 26L, 27L, 28L, 29L, 30L,
31L, 33L, 34L, 35L, 36L, 37L, 38L), class = "data.frame")
我的模型参数估计如下:
estimate se zval pval ci.lb ci.ub
intrcpt 1.1422 0.3862 2.9575 0.0031 0.3852 1.8991 **
Height_RR 0.3412 0.1488 2.2925 0.0219 0.0495 0.6328 *
CWD 0.0014 0.0006 2.2698 0.0232 0.0002 0.0026 *
Height_RR:CWD -0.0006 0.0002 -3.0161 0.0026 -0.0009 -0.0002 **
我想使用图表显示此结果的预测,其中x和y轴都是连续预测变量,预测值由颜色渐变表示。使用此代码,我得到下图
library(ggplot2)
new.data<-expand.grid(Height_RR=seq(min(df$Height_RR),max(df$Height_RR),length.out = 20),
CWD=seq(min(df$CWD,na.rm = T),max(df$CWD,na.rm = T),length.out = 20))
new.data$yi<-(new.data$Height_RR*0.3412)+1.1422+(0.0014*new.data$CWD)+((new.data$CWD*new.data$Height_RR)*0.0006)
ggplot(new.data,aes(x=Height_RR,y=CWD,fill=yi))+geom_raster()+scale_fill_continuous(low="light grey",high="black")
但是,我没有该图的所有区域的数据,因此我推断这个模型。下图中的最小凸包和点显示了我的数据
的位置我的问题是:
答案 0 :(得分:4)
这是一个想法,我希望我做对了..
# Create a convex hull of the points in df and turn that into a polygon of class SpatialPolygons:
ch <- chull(df$Height_RR, df$CWD)
poly.df <- df[c(ch, ch[1]),]
poly <- SpatialPolygons(list(Polygons(list(Polygon(as.matrix(poly.df[,1:2]))),1)))
# Create a SpatialPointsDataFrame with new.data:
library(sp)
new.data.poly <- new.data
coordinates(new.data.poly) <- ~Height_RR+CWD
# Extract the points in new.data which are covered by the polygon:
new.data$inp <- over(new.data.poly, poly)
new.data <- new.data[complete.cases(new.data),]
# Calculate yi as you did:
new.data$yi<-(new.data$Height_RR*0.3412) + 1.1422 + (0.0014*new.data$CWD) + ((new.data$CWD*new.data$Height_RR)*0.0006)
# Plot:
ggplot(new.data, aes(x=Height_RR,y=CWD,fill=yi)) +
geom_raster() +
scale_fill_continuous(low="light grey",high="black")
答案 1 :(得分:0)
您可以使用dismo :: convHull来估计和预测(确定数据是否在其中)凸包。然后你可以用它来掩盖当前情节中落在船体外面的细胞。
答案 2 :(得分:0)