Question

我正在使用按钮在视图中显示图像。当我点击它时，我试图为每个图像打开一个不同的活动。

    package com.union.pr26;

    import android.app.Activity;
    import android.content.Intent;
    import android.os.Bundle;
    import android.support.v4.view.ViewPager;
    import android.view.View;

    import java.util.ArrayList;


    public class MainActivity extends Activity {
    ViewPager viewPager;
    CustomeSwipeAdapter adapter;
       ArrayList<Class>list=new ArrayList<Class>();
    list.add(Class(Main2Activity.class))

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        viewPager=(ViewPager)findViewById(R.id.viewpager);
        adapter=new CustomeSwipeAdapter(this);
        viewPager.setAdapter(adapter);

    }
    public void activity(View v){
     Class activityClass=list.get(1);
        Intent intent =new Intent(this,activityClass);
        startActivity(intent);
    }
}

适配器：

    package com.union.pr26;

    import android.content.Context;
    import android.support.v4.view.PagerAdapter;
    import android.view.LayoutInflater;
    import android.view.View;
    import android.view.ViewGroup;
    import android.widget.ImageView;
    import android.widget.LinearLayout;

    public class CustomeSwipeAdapter extends PagerAdapter {
    private Context ctx;
    final int position = 0;
    private LayoutInflater layoutInflater;
    private int []imgID ={R.drawable.img1,R.drawable.img2,R.drawable.img3};
    public CustomeSwipeAdapter(Context ctx) {
        this.ctx=ctx;
    }

    @Override
    public int getCount() {
        return imgID.length;
    }

    @Override
    public boolean isViewFromObject(View view, Object object) {
        return (view==(LinearLayout)object);
    }

    @Override
    public Object instantiateItem(ViewGroup container, int position) {
        layoutInflater =(LayoutInflater)ctx.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        View item_view =layoutInflater.inflate(R.layout.extra,container,false);
        ImageView imageView =(ImageView)item_view.findViewById(R.id.imageView);
        imageView.setImageResource(imgID[position]);
        container.addView(item_view);
        return item_view;
    }

    @Override
    public void destroyItem(ViewGroup container, int position, Object object) {
        container.removeView((LinearLayout)object);
    }
}

Answer 1

制作此内容，根据需要多次复制并粘贴，并将其更改为您想要的活动。确保你不要打开多个布局，否则会弄乱它。希望这会有所帮助。

Intent intent = new Intent(MainComp_Banner.this, MainComp_Banner_edit.class);
                startActivity(intent);

将此添加到您的清单，以便它不会让您崩溃，为您要启动的每个活动执行此操作。

 <activity
        android:name=".MainComp_Banner_edit"
        android:label="EditBanner"
        android:screenOrientation="portrait"
        android:theme="@style/AppTheme.NoActionBar"/>

如何在android中打开多个活动

1 个答案: