Question

我一直在使用Ruby中的计算器来掌握基础知识。我从用户那里得到了他们告诉我操作的输入，然后我用空格（＆＃39;＆＃39;）作为分隔符拆分字符串，并根据字符串包含的操作符，我执行那个操作。我试图让乘法工作先行，但我不能让它工作。除了从字符串到int的转换外，一切正常。

puts "Hey? What's your name?"

user =  gets.chomp
user.capitalize!

puts "Operation please"
operation = gets.chomp
operation = operation.split(' ')

answer = 1

operation.each { |var|
    next if var == "*"
    var.to_i
    answer = var*answer
}

puts "The answer is #{answer}, is that right?"
confirm = gets.chomp

Answer 1

var.to_i本身并没有改变它所要求的东西。执行此操作的方法通常以爆炸结束（即!）来表示，尽管有些人不这样做（请参阅评论）。

使用分配：var = var.to_i。

Answer 2

你快到了，你只需要将to_i的结果保存到变量中。如您所见，操作不到位，您必须存储结果：

2.0.0-p648 :003 > a = '3'
 => "3"
2.0.0-p648 :004 > a.to_i
 => 3
2.0.0-p648 :005 > a
 => "3"
2.0.0-p648 :006 > b = a.to_i
 => 3
2.0.0-p648 :007 > b
 => 3

Answer 3

尝试一下，我已经尝试过它并且有效！

puts "Hey? What's your name?"

user =  gets.chomp
user.capitalize!

puts "Operation please"
operation = gets.chomp
operation = operation.split(' ')

answer = 1

operation.each do |var|
  next if var == "*"
  answer = (var.to_i * answer)
end

puts "The answer is #{answer}, is that right?"
confirm = gets.chomp

Ruby：从字符串转换为int

3 个答案: