在Django中,只将表迁移到2个数据库中的2个数据库

时间:2016-03-16 20:49:59

标签: python django

我正在尝试在1个数据库中有选择地创建表,而不是另一个。

在我的示例中,我只想为tlocation数据库中的应用创建表:tcategorytransforms。但是,Django正在transforms数据库中创建所有表。

这是DB路由器配置:

TRANSFORM_APPS = ('tcategory', 'tlocation')


class TransformRouter(object):
    """
    A router to control all database operations on models in the
    "utils_transform" application.
    """
    def db_for_read(self, model, **hints):
        """
        Attempts to read 'transforms' models go to 'transforms' database.
        """
        if model._meta.app_label in TRANSFORM_APPS:
            return 'transforms'
        return None

    def db_for_write(self, model, **hints):
        """
        Attempts to write 'transforms' models go to 'transforms' database.
        """
        if model._meta.app_label in TRANSFORM_APPS:
            return 'transforms'
        return None

    def allow_relation(self, obj1, obj2, **hints):
        """
        Allow relations if a model in the 'tlocation' app is involved.
        """
        if obj1._meta.app_label in TRANSFORM_APPS or \
           obj2._meta.app_label in TRANSFORM_APPS:
           return True
        return None

    def allow_migrate(self, db, app_label, model=None, **hints):
        """
        Make sure the 'tlocation' app only appears in the 'transforms'
        database.
        """
        if app_label in TRANSFORM_APPS:
            return db == 'transforms'
        return None


class DefaultRouter(object):
    """
    Catch-all Router for all other DB transactions that aren't in the 
    ``utils_transform`` app.
    """

    def db_for_read(self, model, **hints):
        return 'default'

    def db_for_write(self, model, **hints):
        return 'default'

    def allow_relation(self, obj1, obj2, **hints):
        if obj1._state.db == obj2._state.db:
           return True
        return None

    def allow_migrate(self, db, app_label, model=None, **hints):
        return None

我用来运行迁移的命令是:

./manage.py migrate --database=transforms

当我一次只迁移1个应用时,如下所示,这是有效的。但是如果没有migrate命令中的应用过滤器,我就无法运行。例如:

./manage.py migrate tlocation --database=transforms
./manage.py migrate tcategory --database=transforms

1 个答案:

答案 0 :(得分:2)

您是否尝试过managed = False您想要创建表格的模型?

class MyModel(models.Model):
    ...
    class Meta:
        managed = False