我想要的是仅使用两列进行搜索。并在搜索时排除列电子邮件。谢谢 这是我的javascript代码
<script type="text/javascript">
function doSearch() {
var searchText = document.getElementById('searchTerm').value;
var targetTable = document.getElementById('report');
var targetTableColCount;
//Loop through table rows
for (var rowIndex = 0; rowIndex < targetTable.rows.length; rowIndex++ ) {
var rowData = '';
//Get column count from header row
if (rowIndex == 0) {
targetTableColCount = targetTable.rows.item(rowIndex).cells.length;
continue; //do not execute further code for header row.
}
//Process data rows. (rowIndex >= 1)
for (var colIndex = 0; colIndex < targetTableColCount; colIndex++) {
var cellText = '';
if (navigator.appName == 'Microsoft Internet Explorer')
cellText = targetTable.rows.item(rowIndex).cells.item(colIndex).innerText;
else
cellText = targetTable.rows.item(rowIndex).cells.item(colIndex).textContent;
rowData += cellText;
}
// Make search case insensitive.
rowData = rowData.toLowerCase();
searchText = searchText.toLowerCase();
//If search term is not found in row data
//then hide the row, else show
if (rowData.indexOf(searchText) == -1)
targetTable.rows.item(rowIndex).style.display = 'none';
else
targetTable.rows.item(rowIndex).style.display = 'table-row';
}
}
</script>
这是我的HTML代码
<input id="searchTerm" class="form-control" placeholder="Enter text" onkeyup="doSearch()">
<table id="report" class="table">
<thead>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Email</th>
</tr>
</thead>
<tbody>
<tr>
<td>John</td>
<td>Doe</td>
<td>john@example.com</td>
</tr>
<tr>
<td>Mary</td>
<td>Moe</td>
<td>mary@example.com</td>
</tr>
<tr>
<td>July</td>
<td>Dooley</td>
<td>july@example.com</td>
</tr>
</tbody>
</table>
我有另一个问题。我在我的html表上添加了一个可扩展的行 现在搜索没有给出所需的输出。例如,当我搜索不在html表上的值时,它只删除第一行并显示行的其余部分。这不是正确的输出。
<table id="report" class="table">
<thead>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Email</th>
<th></th>
</tr>
</thead>
<tbody>
<tr>
<td>John</td>
<td>Doe</td>
<td>john@example.com</td>
<td>
<div class="arrow"><a id="menu-toggle" href="#" ><i class="glyphicon glyphicon-plus-sign"></i></a></div>
</td>
</tr>
<tr><td colspan="4">
<button type="button" class="btnview btn btn-xs btn-warning" >
<span class="glyphicon glyphicon-remove-circle" aria-hidden="true"></span>View
</button>
</td>
</tr>
<tr>
<td>Mary</td>
<td>Moe</td>
<td>mary@example.com</td>
<td>
<div class="arrow"><a id="menu-toggle" href="#" ><i class="glyphicon glyphicon-plus-sign"></i></a></div>
</td>
</tr>
<tr><td colspan="4">
<button type="button" class="btnview btn btn-xs btn-warning" >
<span class="glyphicon glyphicon-remove-circle" aria-hidden="true"></span>View
</button>
</td>
</tr>
<tr>
<td>July</td>
<td>Dooley</td>
<td>july@example.com</td>
<td>
<div class="arrow"><a id="menu-toggle" href="#" ><i class="glyphicon glyphicon-plus-sign"></i></a></div>
</td>
</tr>
<tr><td colspan="4">
<button type="button" class="btnview btn btn-xs btn-warning" >
<span class="glyphicon glyphicon-remove-circle" aria-hidden="true"></span>View
</button>
</td>
</tr>
</tbody>
</table>
将您的代码整合到我的代码之后,罗马先生。搜索现在按预期工作。但当searchterm输入为空时我按下退格键。它变得像这样
答案 0 :(得分:1)
我相信这应该可以回答你的问题。我只是调整您要搜索的列数:
$this->db->join('table1name pr1','pr1.id = u.tb1_id','right');
$this->db->join('table2name tb2','tb2.id = u.tb2_id','right');
以下是一个例子:
http://codepen.io/anon/pen/PNWNmL
<强> 更新 强>
好的,我不确定这是否适合您正在寻找的内容,但我只是注释掉了导致该按钮在退回时显示的代码。这是我做的:
for (var colIndex = 0; colIndex < (targetTableColCount-1); colIndex++) {
这是一个jsfiddle:
答案 1 :(得分:1)
包含额外要求的解决方案(表格中有可扩展的行):
- 替换嵌套的for
循环(通过行列),如下所示:
(您还应该跳过处理中只有一个单元格(td)的行)
...
var rowCells = targetTable.rows.item(rowIndex).cells, cellsLen = rowCells.length;
if (cellsLen > 1) {
for (var colIndex = 0; colIndex < 2; colIndex++) {
var cellText = '';
if (targetTable.rows.item(rowIndex).cells.item(colIndex)) {
cellText = rowCells.item(colIndex)[(navigator.appName == 'Microsoft Internet Explorer')? "innerText" : "textContent"];
}
rowData += cellText;
}
}
// Make search case insensitive.
rowData = rowData.toLowerCase().trim();
searchText = searchText.toLowerCase();
//If search term is not found in row data
//then hide the row, else show
if (cellsLen > 1) {
if (searchText && rowData.indexOf(searchText) === -1) {
targetTable.rows.item(rowIndex).style.display = 'none';
} else {
targetTable.rows.item(rowIndex).style.display = 'table-row';
}
}
...