我已经在这段代码上工作了一段时间,我几乎让它工作但我遇到了问题。我在排序数据时丢失了数据。我输入的数字越多,数字越多,显示的是整数。 link to the image of my output
此外,一旦代码运行,我将收到一个带有此消息的弹出窗口(我注意到在我添加了sum函数和之后的每个函数并且我没有按F12时出现此错误):
“Windows在project3.exe中触发了断点。
这可能是由于堆的损坏,这表示project3.exe或它已加载的任何DLL中存在错误。
这也可能是由于用户在按下F12时 project3.exe具有焦点。
输出窗口可能包含更多诊断信息。 “
这是我的代码: 在最后编号的输入后询问用户输入数字,他们必须按0,它显示数据,显示一些统计数据并对数据进行排序。 我没有检查用户错误
(*如果我不使用system("pause")
,终端窗口会关闭,这就是为什么它就在那里我知道我应该'delete []arr
但它会在我放零后给我断点信息这就是为什么它被评论出来)
#include <iostream>
#include <iomanip>
using namespace std;
void getdata(double *arr, double &data, int &floatpt);
void display (double *arr, int floatpt);
void computesum (double *arr, int floatpt, double sum);
void computearthmeticmean (double *arr, int floatpt, double aMean);
void computeharmonicmean (double *arr, int floatpt, double hMean);
void median(double *arr, int floatpt);
void sort (double *arr, int floatpt);
int main ()
{
double data, sum=0, aMean=0, hMean=0;
int count=0, floatpt;
double *arr =new double[count];
getdata (arr, data, floatpt);
cout<<"Thank you. The data you entered are "<<endl;
display(arr, floatpt);
cout<<"The following statistics were computed "<<endl;
computesum(arr,floatpt, sum);
computearthmeticmean(arr, floatpt, aMean);
median(arr, floatpt);
computeharmonicmean (arr, floatpt, hMean);
sort(arr, floatpt);
cout<<"The original data set is "<<endl;
display(arr, floatpt);
cout<<"Thank you for using this program. Enjoy your statistics "<<endl;
//delete []arr;
system ("pause");
return 0;
}
void getdata(double *arr, double &data, int &floatpt)
{
int count=0;
cout<<"Please enter floating point data.\n";
cout<<"After the last number has been entered press 0 (zero) \n";
do
{
cin>>arr[count];
data = arr[count];
count++;
}while(data != 0);
floatpt=(count-1);
}
void display (double *arr, int floatpt)
{
for(int i=0; i<floatpt; i++)
{
cout<<arr[i]<<endl;
}
}
void computesum (double *arr, int floatpt, double sum)
{
for (int j=0; j<floatpt; j++)
{
sum+=arr[j];
}
cout<<"Sum: "<<sum<<endl;
}
void computearthmeticmean (double *arr, int floatpt, double aMean)
{
for (int a=0; a<floatpt; a++)
{
aMean+=arr[a];
}
aMean=aMean/floatpt;
cout<<"Arithmetic Mean: "<<aMean<<endl;
}
void computeharmonicmean (double *arr, int floatpt, double hMean)
{
for (int h=0; h<floatpt; h++)
{
hMean+=(1/arr[h]);
}
hMean=floatpt/hMean;
cout<<"Harmonic Mean: "<<hMean<<endl;
}
void median(double *arr, int floatpt)
{
int temp;
double median;
for (int s=0; s<floatpt; s++)
{
for (int r=0; r<(floatpt-1); ++r)
{
if (arr[r] > arr[r+1])
{
temp = arr[r];
arr[r] = arr[r+1];
arr[r+1] = temp;
}
}
if (floatpt%2 == 0)
{
median = (arr[s/2] + arr[(s/2)-1])/2.0;
}
else
{
median = arr[s/2]/1.0;
}
}
cout<<"Median: "<<median<<endl;
}
void sort (double *arr, int floatpt)
{
cout<<"The sorted data set is: "<<endl;
for (int sd=0; sd<floatpt; sd++)
{
cout<<arr[sd]<<endl;
}
}
答案 0 :(得分:1)
int count=0, floatpt;
double *arr =new double[count];
count
为0,因此您创建的数组没有分配。因此,在getdata
中,您会读入超出范围的内存位置。
您打算稍后重新分配吗?
也许如果您尝试使用std::vector<double>
,那么事情就会成功。它会自动调整大小,并且可以很容易地进行边界检查。
像这样(未经测试):
#include <vector>
// ...
std::vector<double> data;
getdata(arr);
// ...
void getdata(std::vector<double>& arr)
{
double nextValue;
cout<<"Please enter floating point data.\n";
cout<<"After the last number has been entered press 0 (zero) \n";
cin>>nextValue;
while(nextValue != 0)
{
arr.push_back(nextValue);
cin >> nextValue;
}
}