Question

我有我的nodejs项目，我想从我的route.js中分离记录器以获得干净的代码。

但我有下一个问题，当我尝试将我的记录器加载到route.js文件时，它会显示下一个错误：

TypeError: loggers.getTicketLogger is not a function
    at Object.<anonymous> (/home/ismael/projects/nodejs-ticketing/routes/ticket.js:3:23)
    at Module._compile (module.js:413:34)
    at Object.Module._extensions..js (module.js:422:10)
    at Module.load (module.js:357:32)
    at Function.Module._load (module.js:314:12)
    at Module.require (module.js:367:17)
    at require (internal/module.js:16:19)
    at Object.<anonymous> (/home/ismael/projects/nodejs-ticketing/server.js:49:1)
    at Module._compile (module.js:413:34)
    at Object.Module._extensions..js (module.js:422:10)
    at Module.load (module.js:357:32)
    at Function.Module._load (module.js:314:12)
    at Function.Module.runMain (module.js:447:10)
    at startup (node.js:141:18)
    at node.js:933:3

我的记录器dir中有下一个代码：

记录器/ ticket.js

var log4js = require('log4js');

module.exports = function(){

  getTicketLogger = function(){
    var logger = null;

    log4js.loadAppender('file');
    log4js.addAppender(log4js.appenders.file(__dirname + '/../log/ticket.log'), 'ticket-log');

    logger = log4js.getLogger('ticket-log');
    logger.setLevel('DEBUG');

    return logger;
  }

};

我的route.js文件有下一个头

路由/ ticket.js

var Ticket  = require('../models/ticket'),
    loggers = require('../loggers/ticket.js'),
    log     = loggers.getTicketLogger();

module.exports = function(app){
}

我做错了什么，以及如何改进代码以将记录器与route.js文件分开。

谢谢你。

Answer 1

loggers / ticket.js 应该返回一个包含try catch方法的对象。

getTicketLogger

然后在 routes / ticket.js

中

var log4js = require('log4js');

module.exports = function() {

  var getTicketLogger = function(){
    var logger = null;

    log4js.loadAppender('file');
    log4js.addAppender(log4js.appenders.file(__dirname + '/../log/ticket.log'), 'ticket-log');

    logger = log4js.getLogger('ticket-log');
    logger.setLevel('DEBUG');

    return logger;

  }

  return { getTicketLogger: getTicketLogger };

};

ExpressJS中记录器模块定义的问题

1 个答案: