Question

我的弹性搜索文档看起来像：

{
                "entityFk": 0,
                "entityCode": "ADM",
                "entityObj": {
                    "id": 0,
                    "code": "ADM",
                    "description": "ADM - FIRSTCOM"
                },
                "practiceFk": 54745,
                "practiceObj": {
                    "id": 54745,
                    "code": "33.04.01.32",
                    "description": "Artrotomia ou artroscopia com tratamento de lesões articulares circunscritas  ",
                    "practiceValue": 23.5
                }
            }
        }

我想将所有具有entityCode.description等于“FIRST”的“practiceValue”（非null）加起来，所以我提出了这个问题：

    {
    "size" : 0,
    "query" : {
        "bool" : {
            "must_not" : [
                {
                    "missing" : { "field" : "practiceObj.practiceValue" }
                }
             ],
             "must" : [
                {
                    "match" : { "entityObj.description" : "FIRST" }
                }
             ]
         }
    },
    "aggs" : {
        "total" : {  
            "sum" : { "field" : "practiceObj.practiceValue"} 

        }
    }
}

以下是我获得的结果：

   {
    "took": 26,
    "timed_out": false,
    "_shards": {
        "total": 5,
        "successful": 5,
        "failed": 0
    },
    "hits": {
        "total": 11477,
        "max_score": 0,
        "hits": []
    },
    "aggregations": {
        "total": {
            "value": 1593598.7499999984
        }
    }
}

交易是：我怎样才能将值四舍五入到小数点后2位。有人可以帮忙吗？感谢。

编辑：

这是我的映射：

 {
    "index_practice_entities": {
        "mappings": {
            "practice_entities_search": {
                "properties": {
                    "entityCode": {
                        "type": "string"
                    },
                    "entityFk": {
                        "type": "long"
                    },
                    "entityObj": {
                        "properties": {
                            "code": {
                                "type": "string"
                            },
                            "description": {
                                "type": "string"
                            },
                            "id": {
                                "type": "long"
                            }
                        }
                    },
                    "practiceFk": {
                        "type": "long"
                    },
                    "practiceObj": {
                        "properties": {
                            "code": {
                                "type": "string"
                            },
                            "description": {
                                "type": "string"
                            },
                            "id": {
                                "type": "long"
                            },
                            "practiceValue": {
                                "type": "double"
                            }
                        }
                    }
                }
            }
        }
    }
}

Answer 1

请尝试下面提到的脚本，它会将聚合值四舍五入到小数位。

"aggs" : {
        "total" : {  
            "sum" : { 
              "script" : "Math.round(doc['practiceObj.practiceValue'].value*100)/100.0"
               } 

        }
    }

Answer 2

您可以尝试script来实现这一目标：

 "aggs" : {
    "total" : {  
        "sum" : { "script" : "(doc['practiceObj.practiceValue'].value).round(2)"  // practiceValue should be double or float
        } 

    }
}

确保to enable scripting

Answer 3

我写了一篇aggs用于更精确地管理弹性浮点的总和：

{
   "query":{
       /* your's filters */
   },
   "aggs":{
      "price":{
         "sum":{
            "field":"price",
            "script":"BigDecimal.valueOf(_value).setScale(4, RoundingMode.HALF_UP)",
            "missing":0
         }
      }
   }
}

在此示例中，您可以管理将.setScale更改为2的比例。

如何向上舍入到小数点后两位 - elasticsearch

3 个答案: