Question

修改成功：函数（RES） { var costData = []; var costData2 = [];

        costData.push(res['income']);
        costData2.push(res['instIncome']);



        var areaChartData = {
          labels: ["January", "February", "March", "April", "May", "June", "July", "August"
          , "September", "October", "November", "December"],
          datasets: [
            {
              label: "Cash Income",
              strokeColor: "rgba(210, 214, 222, 1)",
              pointColor: "rgba(210, 214, 222, 1)",
              pointStrokeColor: "#c1c7d1",
              pointHighlightFill: "#fff",
              pointHighlightStroke: "rgba(220,220,220,1)",
              data: costData
            }
          ]
        };
        var barChartCanvas = $("#barChart").get(0).getContext("2d");
        var barChart = new Chart(barChartCanvas);
        var barChartData = areaChartData;
        barChartData.datasets[0].fillColor = "#00a65a";
        barChartData.datasets[0].strokeColor = "#00a65a";
        barChartData.datasets[0].pointColor = "#00a65a";
        var barChartOptions = {
          //Boolean - Whether the scale should start at zero, or an order of magnitude down from the lowest value
          scaleBeginAtZero: true,
          //Boolean - Whether grid lines are shown across the chart
          scaleShowGridLines: true,
          //String - Colour of the grid lines
          scaleGridLineColor: "rgba(0,0,0,.05)",
          //Number - Width of the grid lines
          scaleGridLineWidth: 1,
          //Boolean - Whether to show horizontal lines (except X axis)
          scaleShowHorizontalLines: true,
          //Boolean - Whether to show vertical lines (except Y axis)
          scaleShowVerticalLines: true,
          //Boolean - If there is a stroke on each bar
          barShowStroke: true,
          //Number - Pixel width of the bar stroke
          barStrokeWidth: 2,
          //Number - Spacing between each of the X value sets
          barValueSpacing: 5,
          //Number - Spacing between data sets within X values
          barDatasetSpacing: 1,
          //String - A legend template
          legendTemplate: "<ul class=\"<%=name.toLowerCase()%>-legend\"><% for (var i=0; i<datasets.length; i++){%><li><span style=\"background-color:<%=datasets[i].fillColor%>\"></span><%if(datasets[i].label){%><%=datasets[i].label%><%}%></li><%}%></ul>",
          //Boolean - whether to make the chart responsive
          responsive: true,
          maintainAspectRatio: true
        };

        barChartOptions.datasetFill = false;
        barChart.Bar(barChartData, barChartOptions);
      }

这是PHP代码：

    $sql = "SELECT 
    sum(cost) as cost

FROM 
(
    SELECT 
        sum(project_cost) as cost, 
        month(date_now) as month 
    FROM 
        dentist.patient_info 
    WHERE id_logged=:logged AND year(date_now)=:year_now AND payment_type=:pt 
    GROUP BY month(date_now)
    UNION
    SELECT 
        sum(payment), 
        month(date_now) 
    FROM 
       debt
    WHERE year(debt.date_now)=:year_now
    UNION SELECT 0,1
    UNION SELECT 0,2
    UNION SELECT 0,3
    UNION SELECT 0,4
    UNION SELECT 0,5
    UNION SELECT 0,6
    UNION SELECT 0,7
    UNION SELECT 0,8
    UNION SELECT 0,9
    UNION SELECT 0,10
    UNION SELECT 0,11
    UNION SELECT 0,12
) tmp
GROUP BY month";
$sqlStmt = $conn->prepare($sql);
$sqlStmt->bindValue(":logged", $id_logged);
$sqlStmt->bindValue(":pt", $c);
$sqlStmt->bindValue(":year_now", $date1);
$exec = $sqlStmt->execute();
$res1 = $sqlStmt->fetchAll();

$sql2 = "SELECT 
    sum(cost) as cost

FROM 
(
    SELECT 
        sum(payment) as cost, 
        month(date_now) as month 
    FROM 
        debt 
    WHERE id_logged=:logged AND year(date_now)=:year_now  
    GROUP BY month(date_now)

    UNION SELECT 0,1
    UNION SELECT 0,2
    UNION SELECT 0,3
    UNION SELECT 0,4
    UNION SELECT 0,5
    UNION SELECT 0,6
    UNION SELECT 0,7
    UNION SELECT 0,8
    UNION SELECT 0,9
    UNION SELECT 0,10
    UNION SELECT 0,11
    UNION SELECT 0,12
) tmp
GROUP BY month";
$sqlStmt2 = $conn->prepare($sql2);
$sqlStmt2->bindValue(":logged", $id_logged);
$sqlStmt2->bindValue(":year_now", $date1);
$exec2 = $sqlStmt2->execute();
$res2 = $sqlStmt2->fetchAll();

$res['income']=$res1;
$res['instIncome']=$res2;

echo json_encode($res);

结果：

没有数据显示

结束编辑

我有这个PHP代码，每个月的收入总和：

$res = array();
    $c = "cash";
    $i = "installment";
    //SUM of cash paid Month
    $sql = "SELECT 
    sum(cost) as cost

FROM 
(
    SELECT 
        sum(project_cost) as cost, 
        month(date_now) as month 
    FROM 
        dentist.patient_info 
    WHERE id_logged=:logged AND year(date_now)=:year_now AND payment_type=:pt 
    GROUP BY month(date_now)
    UNION
    SELECT 
        sum(payment), 
        month(date_now) 
    FROM 
       debt
    WHERE year(debt.date_now)=:year_now
    UNION SELECT 0,1
    UNION SELECT 0,2
    UNION SELECT 0,3
    UNION SELECT 0,4
    UNION SELECT 0,5
    UNION SELECT 0,6
    UNION SELECT 0,7
    UNION SELECT 0,8
    UNION SELECT 0,9
    UNION SELECT 0,10
    UNION SELECT 0,11
    UNION SELECT 0,12
) tmp
GROUP BY month";
$sqlStmt = $conn->prepare($sql);
$sqlStmt->bindValue(":logged", $id_logged);
$sqlStmt->bindValue(":pt", $c);
$sqlStmt->bindValue(":year_now", $date1);
$exec = $sqlStmt->execute();
$res = $sqlStmt->fetchAll();

echo json_encode($res);

结果将发送回AJAX成功函数，并使用ChartJS显示在条形图中。

现在我需要在同一个图表上创建另一个结果栏。这是脚本：

success:function(res)
    {
      var costData = [];
      $.each(res, function( key, row)
      {
        costData.push(row['cost']);
      });


        var areaChartData = {
          labels: ["January", "February", "March", "April", "May", "June", "July", "August"
          , "September", "October", "November", "December"],
          datasets: [
            {
              label: "Cash Income",
              strokeColor: "rgba(210, 214, 222, 1)",
              pointColor: "rgba(210, 214, 222, 1)",
              pointStrokeColor: "#c1c7d1",
              pointHighlightFill: "#fff",
              pointHighlightStroke: "rgba(220,220,220,1)",
              data: costData
            }
          ]
        };
        var barChartCanvas = $("#barChart").get(0).getContext("2d");
        var barChart = new Chart(barChartCanvas);
        var barChartData = areaChartData;
        barChartData.datasets[0].fillColor = "#00a65a";
        barChartData.datasets[0].strokeColor = "#00a65a";
        barChartData.datasets[0].pointColor = "#00a65a";
        var barChartOptions = {
          //Boolean - Whether the scale should start at zero, or an order of magnitude down from the lowest value
          scaleBeginAtZero: true,
          //Boolean - Whether grid lines are shown across the chart
          scaleShowGridLines: true,
          //String - Colour of the grid lines
          scaleGridLineColor: "rgba(0,0,0,.05)",
          //Number - Width of the grid lines
          scaleGridLineWidth: 1,
          //Boolean - Whether to show horizontal lines (except X axis)
          scaleShowHorizontalLines: true,
          //Boolean - Whether to show vertical lines (except Y axis)
          scaleShowVerticalLines: true,
          //Boolean - If there is a stroke on each bar
          barShowStroke: true,
          //Number - Pixel width of the bar stroke
          barStrokeWidth: 2,
          //Number - Spacing between each of the X value sets
          barValueSpacing: 5,
          //Number - Spacing between data sets within X values
          barDatasetSpacing: 1,
          //String - A legend template
          legendTemplate: "<ul class=\"<%=name.toLowerCase()%>-legend\"><% for (var i=0; i<datasets.length; i++){%><li><span style=\"background-color:<%=datasets[i].fillColor%>\"></span><%if(datasets[i].label){%><%=datasets[i].label%><%}%></li><%}%></ul>",
          //Boolean - whether to make the chart responsive
          responsive: true,
          maintainAspectRatio: true
        };

        barChartOptions.datasetFill = false;
        barChart.Bar(barChartData, barChartOptions);
      }

我的问题出在PHP代码中。我应该如何添加另一个查询并获取变量$res2并将其与$res合并，然后我将它们分成i.e $res['income'] and $res['outcome']中的success:function。

如何将一对提取的数组发送到一个json_encode

Answer 1

在你的PHP代码中

$res1 = $sqlStmt->fetchAll();
$res2 = $sqlStmt2->fetchAll(); // Assuming u have executed 2nd query.
$res['income'] = $res1; 
$res['outcome'] = $res2;
echo json_encode($res);

你的Ajax成功

success:function(res){

   $incomeData = res['income'];
   $outcomeData = res['outcome'];

}

将2个获取的结果发送到AJAX

1 个答案: