Question

首先，我有这个返回所有足球比赛的日期

HomeShotsOnTarget（HST）= FullTimeHomeGoals（FTHG）

或

AwayShotsOnTarget（AST）= FullTimeAWayGoals（FTHG）

SELECT MatchDate, HomeTeam, AwayTeam 
FROM matches 
WHERE HST=FTHG or AST=FTAG

显示

MatchDate | HomeTeam | AwayTeam
2003/08/23    17          32
2003/09/13    24          39

依旧等......

HomeTeam和AwayTeam下的数字是TeamCodes，它们在另一个名为club的表中，也有团队的真名。

以下内容将HomeTeam的TeamCode与表俱乐部中的RealName相匹配。

SELECT MatchDate, RealName
FROM club T1 
INNER JOIN matches T2 ON T1.TeamCode = T2.HomeTeam

显示

MatchDate|  RealName|
2003/08/23  Arsenal
2003/09/13 Blackburn

等等...

所以我的问题是我似乎找不到在HomeTeam和AwayTeam下显示RealName而不是TeamCode的方法。像这样......

MatchDate | HomeTeam | AwayTeam
2003/08/23   Arsenal   Aston Villa
2003/09/13   Blackburn  Man Utd

Answer 1

可能是这样的：

SELECT MatchDate, homeTeam.RealName AS HomeTeam, awayTeam.RealName AS AwayTeam
FROM matches m
INNER JOIN club homeTeam ON (m.HomeTeam = homeTeam.TeamCode)
INNER JOIN club awayTeam ON (m.AwayTeam = awayTeam.TeamCode);

我用来放置一些含义标签，而不仅仅是T1和T2。

Answer 2

你只需要另外加入Away Team的俱乐部牌桌，就像这样：

SELECT MatchDate, T1.RealName AS HomeTeamName, T3.RealName AS AwayTeamName 
FROM club T1 
INNER JOIN matches T2 ON T1.TeamCode = T2.HomeTeam 
INNER JOIN club T3 ON T3.TeamCode = T2.AwayTeam

Answer 3

您只需加入Team-Table两次，请尝试以下查询：

SELECT 
  MatchDate, 
  T1.RealName, 
  T2.RealName 
FROM 
  matches INNER JOIN club T1 ON (matches.HomeTeam = T1.TeamCode)
          INNER JOIN club T2 ON (matches.AwayTeam = T2.TeamCode)
WHERE 
  HST=FTHG OR AST=FTAG

MySQL - 在单独的列中显示两个内部联接

3 个答案: