Question

问题：

为什么变量（ resultVisitor ）返回undefined？

当我在函数 searchVisitors（）中记录命中时，日志返回一个对象数组？

任何想法？

  /* Get passanten telling */
  var searchVisitorParams = {
    index: 'veenendaal',
    type: 'passanten',
    size: 100,
    body: {
      fields: ["Tijdsperiode", "201_WE_Veenendaal", "940_HEMA_Veenendaal"],
      query: {
        "match_all": {}
      },
      sort: {
        Tijdsperiode: "asc"
      }
    }
  };

  function searchVisitors() {
    client.search(searchVisitorParams).then(function (body) {
      var hits = body.hits.hits;
      console.log(hits)
      return hits;
    });
  }

  var resultVisitor = searchVisitors();
  console.log(resultVisitor)

Answer 1

返回在回调函数中。我会做这样的事情：

/* Get passanten telling */
var searchVisitorParams = {
  index: 'veenendaal',
  type: 'passanten',
  size: 100,
  body: {
    fields: ["Tijdsperiode", "201_WE_Veenendaal", "940_HEMA_Veenendaal"],
    query: {
      "match_all": {}
    },
    sort: {
      Tijdsperiode: "asc"
    }
  }
};

function searchVisitors(callback) {
  client.search(searchVisitorParams).then(function (body) {
    var hits = body.hits.hits;
    callback(hits);
  });
}

searchVisitors(function(hits){ // Results are inside hits variable
    console.log(hits);
    // .... Your code ... //
});

弹性搜索JS函数返回值

1 个答案: