您好我正在尝试解析json我的json看起来像:
"data":[[0,1,0],[0,2,0],[0,3,0],[0,4,0],[0,5,0]]
我正在使用以下代码执行操作
int k=0;
for (int j = 1; j <= 7; j++)
{
String data = json.getJSONArray("data").getString(k);
data = data.substring(1, data.length() - 1);
String[] countArr = data.split(",");
}
在Excetion之后我正在考虑;
org.json.JSONException: JSONArray[0] not a string.
at org.json.JSONArray.getString(JSONArray.java:333)
at com.inrev.analytics.manager.impl.IRticsManagerImpl.userActivity(IRFbAnalyticsManagerImpl.java:4276)
at com.inrev.analytics.action.facebook.IRFsightsAction.pageUserActivity(IRFBInsightsAction.java:4004)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:606)
at ognl.OgnlRuntime.invokeMethod(OgnlRuntime.java:870)
at ognl.OgnlRuntime.callAppropriateMethod(OgnlRuntime.java:1293)
at ognl.ObjectMethodAccessor.callMethod(ObjectMethodAccessor.java:68)
答案 0 :(得分:0)
错误很明显。第一个元素不是String
,而是JSONArray
做这样的事情
JSONArray data = json.getJSONArray("data");
for (int i=0; i<data.length(); i++) {
JSONArray element = data.getJSONArray(i);
//Do something with your element
}