我的申请表中有以下表格:
projects
projects_plot_types
项目可以有很多情节类型。我在项目模型中设置了以下关系。
/**
* The plot types that belong to the project.
*
* @return Object
*/
public function plotTypes()
{
return $this->hasMany('App\Models\Project\ProjectsPlotTypes');
}
我希望能够通过在项目模型上查询它的名称来获取情节类型。
我试过这个,但它不起作用:
$project->with('plotTypes')->whereHas('plotTypes', function ($query) use ($row) {
$query->where('name', $row->plot_name);
})->first()->plotTypes->first()->id;
有人能指出我正确的方向吗?
以下评论的$result
输出为:
Project {#705 ▼
#table: "projects"
#fillable: array:7 [▶]
+timestamps: true
#connection: null
#primaryKey: "id"
#perPage: 15
+incrementing: true
#attributes: array:10 [▶]
#original: array:10 [▶]
#relations: array:1 [▼
"plotTypes" => Collection {#769 ▼
#items: array:1 [▼
0 => ProjectsPlotTypes {#774 ▼
#table: "projects_plot_types"
#fillable: array:2 [▶]
+timestamps: false
#connection: null
#primaryKey: "id"
#perPage: 15
+incrementing: true
#attributes: array:4 [▼
"id" => "2"
"project_id" => "1"
"name" => "TYPE 3 - VENTILATION"
"budget" => "245.69"
]
#original: array:4 [▶]
#relations: []
#hidden: []
#visible: []
#appends: []
#guarded: array:1 [▶]
#dates: []
#dateFormat: null
#casts: []
#touches: []
#observables: []
#with: []
#morphClass: null
+exists: true
+wasRecentlyCreated: false
}
]
}
]
#hidden: []
#visible: []
#appends: []
#guarded: array:1 [▶]
#dates: []
#dateFormat: null
#casts: []
#touches: []
#observables: []
#with: []
#morphClass: null
+exists: true
+wasRecentlyCreated: false
}
答案 0 :(得分:1)
也许这就是你要找的东西:
$result = $project->with(['plotTypes' => function($query) use ($row) {
return $query->where('name', $row->plot_name)->first();
}])->first();
dd($result); // print the result and die
更新1
从具有BelongsTo
关系的集合中获取第一个项目:
$plotTypeResult = $result->plotTypes[0]->id;
答案 1 :(得分:1)
您也可以使用下面的连接查询
$result = Illuminate\Support\Facades\DB::table('projects')
->join('projects_plot_types', 'projects_plot_types.id', '=', 'projects.project_plot_id')
->where('projects_plot_types.name', '=', $row->plot_name)
->first();
print_r($result);