Question

我必须与所谓的REST API集成，它根本不是RESTFul。要向特定的GET请求添加更多数据，我必须在URL中发送一个3d数组（丑陋!!）。有没有人知道如何使用Apache HTTP客户端v4.0.1？

以下是PHP中的示例：

$arrArguments['saleData'] = array(); 
$arrArguments['saleData']['invoiceDate'] = 'abcdef';
$arrArguments['saleData']['deliveryDate'] = 'abcdef';
$arrArguments['saleData']['orderData'] = array(); 
$arrArguments['saleData']['orderData'][0] = array(); 
$arrArguments['saleData']['orderData'][0]['productId'] = 'abcdef';
$arrArguments['saleData']['orderData'][0]['description'] = 'abcdef';
$arrArguments['saleData']['orderData'][0]['price'] = 18819;
$arrArguments['saleData']['orderData'][0]['quantity'] = 24389;
$arrArguments['saleData']['orderData'][0]['vatCode'] = 'abcdef';;;;

Answer 1

请试试这个

$arrArguments['saleData'] = array(); 
$arrArguments['saleData']['orderData'] = array(); 
$arrArguments['saleData']['orderData'][0] = array(); 

$arrArguments['saleData']['invoiceDate'] = 'abcdef';
$arrArguments['saleData']['deliveryDate'] = 'abcdef';

$arrArguments['saleData']['orderData'][0]['productId'] = 'abcdef';
$arrArguments['saleData']['orderData'][0]['description'] = 'abcdef';
$arrArguments['saleData']['orderData'][0]['price'] = 18819;
$arrArguments['saleData']['orderData'][0]['quantity'] = 24389;
$arrArguments['saleData']['orderData'][0]['vatCode'] = 'abcdef';

$restUrl ='/saleData/orderData';
new Ajax.Request("<?php echo $this->getUrl($restUrl) ?>", {
                  method: 'Post',
                  parameters: {
                     "saledata" :$arrArguments['saleData']
                               },
                  onComplete: function(response) {
                    console.log(response);  
                  }
              });

如果您使用java / php作为后端语言，则获取请求参数以获取数据。

for java： -

@RequestMapping(value = "/saleData/orderData", method = RequestMethod.GET)
@ResponseBody
public Map<String, Object> beforeEdit(HttpServletRequest request,HttpSession session) {
    Map<String, Object> resultMap = new HashMap<>();
    String requestString = request.getParameter("saledata");//----may this change according to your json parsar 

}

for php

    $saledata = $this->getRequest()->getParam('saledata');

Answer 2

正确答案来自Thilo。您只需添加＆＃34; saleData [OrderData] [0] [productId]＆＃34;作为参数名称而不是指定值。所以你可以这样：

final URIBuilder uriBuilder = new URIBuilder(apiUrl)
        .setPath(this.apiStartPath)
        .setParameter("saleData[OrderData][0][productId]", '12334')
        ......

如何使用Apache HTTP客户端在GET请求中发送3d数组？

2 个答案: