Question

我已将我的用户模型扩展为具有角色，表格如下

users(id,name,email,password,remember_token, role_id,created_at,updated_at)
roles(id,name,description,created_at,updated_at)

然后用户模型

<?php

namespace App;

use Illuminate\Foundation\Auth\User as Authenticatable;

class User extends Authenticatable
{
    /**
     * The attributes that are mass assignable.
     *
     * @var array
     */
    protected $fillable = [
        'name', 'email', 'password',
    ];

    /**
     * The attributes excluded from the model's JSON form.
     *
     * @var array
     */
    protected $hidden = [
        'password', 'remember_token',
    ];

    public function role()
    {
        return $this->hasOne('App\Models\Role', 'id', 'role_id');
    }

}

并且角色模型是

<?php

namespace App\Models;

use Illuminate\Database\Eloquent\Model;

class Role extends Model {

    protected $table = 'roles';

    public function users()
    {
        return $this->hasMany('App\User', 'role_id', 'id');
    }
}

我将用户作为json返回，我希望他们使用查询构建器

来急切地获取角色

$users = DB::table('users')->skip($skip)->take($size)->get();

我得到的输出是

{"id":1,"name":"Vinnie Ashken","email":"ashken@eml.cc","password":"$2y$10$fsSxekoktUV5xqe02hMZIuWVRpykmMvjGa.AJUriCEX.KPRfj.Yk.","role_id":1,"remember_token":"184J9pVLf9N2yQ5YfD9Yf5d88uavn0dCFGsAaXnamXKiIbLugIKAVJTmS1t6","created_at":"2016-03-16 00:23:56","updated_at":"2016-03-16 00:42:56"}

我想要的是

{"id":1,"name":"Vinnie Ashken","email":"ashken@eml.cc","password":"$2y$10$fsSxekoktUV5xqe02hMZIuWVRpykmMvjGa.AJUriCEX.KPRfj.Yk.","role":{"id":1, "name":"Administrator","description":"test"},"remember_token":"184J9pVLf9N2yQ5YfD9Yf5d88uavn0dCFGsAaXnamXKiIbLugIKAVJTmS1t6","created_at":"2016-03-16 00:23:56","updated_at":"2016-03-16 00:42:56"}

Answer 1

尝试使用完整的Eloquent模型（User::）而不是裸查询构建器（DB::table('users')）。然后，您将能够使用with和其他关系方法（除了所有查询构建器方法）：

$users = App\User::with('role')->skip($skip)->take($size)->get();

Laravel 5.2雄辩的关系渴望取得进展

1 个答案: