Question

在javascript函数中，我有一些查询，例如：

sQuery = "select in('E_Edge').@rid as id from ?";
result = db.command ('sql', sQuery,[givenId]);

如果我返回结果，它可能如下所示：

[  
   {  
  "@type":"d",
  "@rid":"#-2:0",
  "@version":0,
  "id":[  
     "#35:62",
     "#35:63",
     "#35:64",
     "#35:65",
     "#35:69"
  ],
  "@fieldTypes":"id=z"
   }
]

如果我想获取ID列表，我可以这样做：

var ids= result[0].getProperty("id");

如果我返回它，我会得到扩展的id，即带有这些id的节点列表。

但是，如果我想迭代它并执行其他操作，ids.length不作为属性存在，则size（）不可用。

如何遍历列表？

Answer 1

如果您希望迭代列表（如果我理解正确）进行其他操作，您可以尝试：

var db=orient.getGraph();
var result=db.command('sql',"select in('E_Edge').@rid as id from Test where @rid='"+rid+"'");

for(i=0;i<result.length;i++)
{
  var ids=result[i].getProperty("id");
  print(ids);
}

如果不是您要找的是什么，您可以更好地解释一下吗？

让我知道。

Answer 2

我尝试了这种结构：

create class Person extends V
create class Movie extends V
create class acts_In extends E
create class directed extends E
create class friend extends E
create class rated extends E

create property Person.name String
create property Person.surname String
create property Movie.title String

create vertex Person set name="Tom", surname="Hanks"
create vertex Person set name="Robin", surname="Wright"
create vertex Person set name="Helen", surname="Hunt"
create vertex Person set name="Robert", surname="Zemeckis"
create vertex Person set name="Russell", surname="Crowe"
create vertex Person set name="Ben", surname="Affleck"
create vertex Person set name="Kevin", surname="Macdonald"
create vertex Person set name="John"
create vertex Person set name="Mark"
create vertex Person set name="Paul"
create vertex Person set name="Mel", surname="Gibson"
create vertex Person set name="Nancy", surname="Meyers"
create vertex Movie set title="Forrest Gump"
create vertex Movie set title="Cast Away"
create vertex Movie set title="State of Play"
create vertex Movie set title="What Women Want"

create edge acts_In from (select from Person where name="Tom" and surname="Hanks") to (select from Movie where title="Forrest Gump")
create edge acts_In from (select from Person where name="Tom" and surname="Hanks") to (select from Movie where title="Cast Away")
create edge acts_In from (select from Person where name="Robin" and surname="Wright") to (select from Movie where title="Forrest Gump")
create edge acts_In from (select from Person where name="Robin" and surname="Wright") to (select from Movie where title="State of Play")
create edge acts_In from (select from Person where name="Helen" and surname="Hunt") to (select from Movie where title="Cast Away")
create edge acts_In from (select from Person where name="Helen" and surname="Hunt") to (select from Movie where title="What Women Want")
create edge acts_In from (select from Person where name="Mel" and surname="Gibson") to (select from Movie where title="What Women Want")
create edge acts_In from (select from Person where name="Russell" and surname="Crowe") to (select from Movie where title="State of Play")
create edge acts_In from (select from Person where name="Ben" and surname="Affleck") to (select from Movie where title="State of Play")
create edge friend from (select from Person where name="Mel" and surname="Gibson") to (select from Person where name="Helen" and surname="Hunt")
create edge friend from (select from Person where name="Ben" and surname="Affleck") to (select from Person where name="Russell" and surname="Crowe")
create edge directed from (select from Movie where title="What Women Want") to (select from Person where name="Nancy" and surname="Meyers")
create edge directed from (select from Movie where title="Cast Away") to (select from Person where name="Robert" and surname="Zemeckis")
create edge directed from (select from Movie where title="Forrest Gump") to (select from Person where name="Robert" and surname="Zemeckis")
create edge directed from (select from Movie where title="State of Play") to (select from Person where name="Kevin" and surname="Macdonald")
create edge rated from (select from Movie where title="What Women Want") to (select from Person where name="Paul")
create edge rated from (select from Movie where title="Cast Away") to (select from Person where name="John")
create edge rated from (select from Movie where title="Forrest Gump") to (select from Person where name="Mark")
create edge rated from (select from Movie where title="State of Play") to (select from Person where name="John")

QUERY ：选择Movie中@rid 13:2行动的演员（'播放状态'）

现在，您可以尝试不同的方法来检索您正在寻找的结果：

使用简单的SELECT FROM @rid查询：

<强> CODE ：

var db = orient.getGraph();
var givenId = '13:2';
var actorsList=[];
var sQuery = "select from ?";
var result = db.command('sql',sQuery, [givenId]);
for(i=0;i<result.length;i++){
  var in_acts_In = result[i].getRecord().field('in_acts_In.out');
  if(in_acts_In!=null){
    var actorsIter=in_acts_In.iterator();
    if(actorsIter!=null){
      while(actorsIter.hasNext()){
        var iteratedActor=actorsIter.next();
        actorsList.push(iteratedActor.getRecord());
      }
    }
  }
}
return actorsList;

<强>输出：

[
    {
        "@type": "d",
        "@rid": "#12:1",
        "@version": 3,
        "@class": "Person",
        "name": "Robin",
        "surname": "Wright",
        "out_acts_In": [
            "#14:2",
            "#14:3"
        ],
        "@fieldTypes": "out_acts_In=g"
    },
    {
        "@type": "d",
        "@rid": "#12:4",
        "@version": 3,
        "@class": "Person",
        "name": "Russell",
        "surname": "Crowe",
        "out_acts_In": [
            "#14:7"
        ],
        "in_friend": [
            "#16:1"
        ],
        "@fieldTypes": "out_acts_In=g,in_friend=g"
    },
    {
        "@type": "d",
        "@rid": "#12:5",
        "@version": 3,
        "@class": "Person",
        "name": "Ben",
        "surname": "Affleck",
        "out_acts_In": [
            "#14:8"
        ],
        "out_friend": [
            "#16:1"
        ],
        "@fieldTypes": "out_acts_In=g,out_friend=g"
    }
]

expand()您的查询结果：

<强> CODE ：

var db=orient.getGraph();
var givenId = '13:2';
var actorsList=[];
var result=db.command('sql',"select expand(in('acts_In')) from ?",[givenId]);
for(i=0;i<result.length;i++)
{
  var actor=result[i].getRecord();
  actorsList.push(actor);;
}
return actorsList;

<强>输出：

[
    {
        "@type": "d",
        "@rid": "#12:1",
        "@version": 3,
        "@class": "Person",
        "name": "Robin",
        "surname": "Wright",
        "out_acts_In": [
            "#14:2",
            "#14:3"
        ],
        "@fieldTypes": "out_acts_In=g"
    },
    {
        "@type": "d",
        "@rid": "#12:4",
        "@version": 3,
        "@class": "Person",
        "name": "Russell",
        "surname": "Crowe",
        "out_acts_In": [
            "#14:7"
        ],
        "in_friend": [
            "#16:1"
        ],
        "@fieldTypes": "out_acts_In=g,in_friend=g"
    },
    {
        "@type": "d",
        "@rid": "#12:5",
        "@version": 3,
        "@class": "Person",
        "name": "Ben",
        "surname": "Affleck",
        "out_acts_In": [
            "#14:8"
        ],
        "out_friend": [
            "#16:1"
        ],
        "@fieldTypes": "out_acts_In=g,out_friend=g"
    }
]

在我的案例中使用输入函数参数（rid且值为13:2）：

<强> CODE ：

var db=orient.getGraph();
var result=db.command('sql',"select in('acts_In').@rid as id from "+rid);
for(i=0;i<result.length;i++)
{
  var idList=result[i].getProperty("id");
}
return idList;

<强>输出：

[
    {
        "@type": "d",
        "@rid": "#12:1",
        "@version": 3,
        "@class": "Person",
        "name": "Robin",
        "surname": "Wright",
        "out_acts_In": [
            "#14:2",
            "#14:3"
        ],
        "@fieldTypes": "out_acts_In=g"
    },
    {
        "@type": "d",
        "@rid": "#12:4",
        "@version": 3,
        "@class": "Person",
        "name": "Russell",
        "surname": "Crowe",
        "out_acts_In": [
            "#14:7"
        ],
        "in_friend": [
            "#16:1"
        ],
        "@fieldTypes": "out_acts_In=g,in_friend=g"
    },
    {
        "@type": "d",
        "@rid": "#12:5",
        "@version": 3,
        "@class": "Person",
        "name": "Ben",
        "surname": "Affleck",
        "out_acts_In": [
            "#14:8"
        ],
        "out_friend": [
            "#16:1"
        ],
        "@fieldTypes": "out_acts_In=g,out_friend=g"
    }
]

希望有所帮助

结果迭代在OrientDB Javascript服务器端函数内部

2 个答案: