当调用presentLocalNotificationNow时,触发didReceiveLocalNotification

时间:2016-03-15 14:10:13

标签: ios iphone uilocalnotification

当我创建本地通知时,会触发回调didReceiveLocalNotification。单击本地通知时会触发相同的回调。目前我通过检查

来划分这两个案例
if ([UIApplication sharedApplication].applicationState == UIApplicationStateInactive) {
    //this means notification is clicked
}

但这里的主要问题是,当您在前台并滑动通知菜单,然后接收本地通知时,将调用此回调didReceiveLocalNotification。在这种情况下,如果我的应用程序进入此。因此,当应用处于非活动状态时,我无法区分点击通知和创建本地通知。关于如何解决这个问题的任何想法?

这是用于安排本地通知的代码:

UILocalNotification* localNotification = [[UILocalNotification alloc] init];
localNotification.alertBody = @"aaaa";
localNotification.alertTitle = @"title";
localNotification.userInfo = myUserInfo;
[[UIApplication sharedApplication] presentLocalNotificationNow:localNotification];

调用此功能后,我会触发didReceiveLocalNotification委托。

2 个答案:

答案 0 :(得分:2)

我必须在我的应用中解决完全相同的问题。我无法在API中找到一种正式的方法来区分,但这是一种解决方法。

创建本地通知时,将当前日期传递到userInfo

localNotification.userInfo = ["alertDate": NSDate()]

当您处理didReceiveLocalNotification时,请再次检查当前日期,以确保它不会在刚刚开始时触发:

if application.applicationState == .Inactive {
    if let alertDate = notification.userInfo?["alertDate"] as? NSDate 
        where (NSDate()).timeIntervalSinceDate(alertDate) > 0.1 {
        // this means notification was initiated by user
    }
}

答案 1 :(得分:0)

UILocalNotification* localNotification = [[UILocalNotification alloc] init];
localNotification.fireDate = [NSDate dateWithTimeIntervalSinceNow:1];
localNotification.alertBody = @"image inserted";
localNotification.timeZone = [NSTimeZone defaultTimeZone];
[[UIApplication sharedApplication] scheduleLocalNotification:localNotification];
[self dismissViewControllerAnimated:YES completion:nil];