我有一个xml文件，Xml代码包含一个没有标签名称和标签属性的段落＆＃34; Id＆＃34;。我需要动态生成一个新的Id。你可以在里面看到一个p标签里面的两行。但它没有标记名称和Id属性。请帮帮我。示例：我需要的行应该像前两行一样。 代码应为DOM
<p id ="271_line_1">My boy are play cricket </p>
<p id ="271_line_2">to win the game. Where they are playing? </p>
<ExampleProgram>
<catalog>
<book id="bk101">
<author>Gambardella, Matthew</author>
<title>XML Developer's Guide</title>
<genre>Computer</genre>
<price>44.95</price>
<publish_date>2000-10-01</publish_date>
<description>An in-depth look at creating applications
with XML.</description>
</book>
<book id="bk102">
<author>Gambardella, Matthew</author>
<p class="paragraph " id="271__paragraph_8">
My boy are play cricket
<iline class="iline_list " id="271_iline_list_9" response="SAMPLE">
<iline class="option " id="271_option_15" prefer="i1">SCHOOL</iline>
<iline class="option " id="271_option_18" prefer="i2">GROUND</iline>
<iline class="option " id="271_option_19" prefer="i4">HOME</iline>
</iline>
to win the game. Where they are playing?
</p>
</book>
<book id="bk103">
<author>Ralls, Kim</author>
<title>Midnight Rain</title>
<genre>Fantasy</genre>
<price>5.95</price>
<publish_date>2000-12-16</publish_date>
<description>A former architect battles corporate zombies,
an evil sorceress, and her own childhood to become queen
of the world.</description>
</book>
</catalog>
</ExampleProgram>
方法更改P标签：现在我可以创建一个p标签，我可以手动设置属性ID。但新的 p标记并未替换父p标记中的文本。我想替换旧文本，我想插入新创建的p标签。我想创建动态ID而不是手动ID。
private static String createPTagId(Node someNode) {
String Id ="271_line_"
NodeList childs = someNode.getChildNodes();
for (int i = 0; i < childs.getLength();i++) {
Node child = childs.item(i);
if (child.getNodeType() == Document.ELEMENT_NODE) {
if (child.getNodeName().equalsIgnoreCase("p")) {
Value = child.getAttributes().getNamedItem("id").getNodeValue();
System.out.println("Attribute Value :" + Value);
printElement(doc);
}
} else {
createPTagId(child);
}
}
if(child.getNodeName().equals("p") && child.getAttributes().getNamedItem("id").getNodeValue().contains(Value)){
Node nextNode = someNode.getFirstChild();
System.out.println("1 "+child.getFirstChild().getNodeValue());
System.out.println("2 "+child.getLastChild().getNodeValue());
String strP= child.getFirstChild().getNodeValue().toString().trim();
String strP1= child.getLastChild().getNodeValue().toString().trim();
int k ;
for( k=1;k<3;k++){
Id = Id.substring(0,Id.length())+k;
System.out.println(Id);
}
Element title = doc.createElement("P");
title.appendChild(doc.createTextNode(strP));
title.setAttribute("id",Id);
nextNode.appendChild(title);
Node nextNodes = someNode.getLastChild();
Element title1 = doc.createElement("P");
title1.appendChild(doc.createTextNode(strP1));
title1.setAttribute("id",Id);
nextNodes.appendChild(title1);
}
}
<catalog>
<book id="bk101">
<author>Gambardella, Matthew</author>
<title>XML Developer's Guide</title>
<genre>Computer</genre>
<price>44.95</price>
<publish_date>2000-10-01</publish_date>
<description>An in-depth look at creating applications
with XML.</description>
</book>
<p class="paragraph " id="271__paragraph_8">
My boy is play cricket
<iline class="iline_list " id="271_iline_list_9" response="SAMPLE">
<iline class="option " id="271_option_15" prefer="i1">wind</iline>
<iline class="option " id="271_option_18" prefer="i2">cloth</iline>
<iline class="option " id="271_option_19" prefer="i4">ribbon</iline>
</iline>
to win the game. Where they are playing?
---<p id ="271_line_">My boy are play cricket </p>---
---<p id ="271_line_">to win the game. Where they are playing? </p>
</p>
<book id="bk102">
<author>Ralls, Kim</author>
<title>Midnight Rain</title>
<genre>Fantasy</genre>
<price>5.95</price>
<publish_date>2000-12-16</publish_date>
<description>A former architect battles corporate zombies,
an evil sorceress, and her own childhood to become queen
of the world.</description>
</book>
</catalog>
我可以创建p标签，但它不会再放在我得到它的同一个地方。它将作为父 P 标记的最后一个子项放置。并且我能够为创建的新P标签动态创建id属性。
新xml：
<Liberary>
<booksInLiberary
class="book_list_1" id="271_book_list_9" response="bookInLiberary">
<p class="paragraph " id="271__paragraph_8">
The Science subject score got increase
<iline class="iline_list " id="271_iline_list_9" response="SAMPLE">
<iline class="option " id="271_option_15" prefer="i1">wind</iline>
<iline class="option " id="271_option_18" prefer="i2">cloth</iline>
<iline class="option " id="271_option_19" prefer="i4">ribbon</iline>
</iline>
,buy coming Exam. Pass percentage 35% increase?
</p>
</bookInLiberary>
<booksWithStudents
class="book_list_2" id="271_book_list_9" response="bookWithStudents">
<p class="paragraph " id="271__paragraph_8">
The Duke unvirsity students renew
<iline class="iline_list " id="271_iline_list_9" response="SAMPLE">
<iline class="option " id="271_option_15" prefer="i1">wind</iline>
<iline class="option " id="271_option_18" prefer="i2">cloth</iline>
<iline class="option " id="271_option_19" prefer="i4">ribbon</iline>
</iline>
the books to study for Exams
</p>
</booksWithStudents>
<Liberary>
答案 0 :(得分：2)
这可能对您有用。我认为以下是您的代码的问题。
以下代码可以满足您的期望。
NodeList pnodes = doc.getElementsByTagName("p");
for(int i=0;i<pnodes.getLength();i++){
NodeList nodes = pnodes.item(i).getChildNodes();
int k = 0;
for(int j = 0;j<nodes.getLength();j++){
if(nodes.item(j).getNodeName().equals("#text")){////Check if the current child element is a text node or not, if yes then replace it with the new P element
k++;
Element title = doc.createElement("P");
title.appendChild(doc.createTextNode(nodes.item(j).getNodeValue()));
String tempId = Id + k; // generate the new Id
title.setAttribute("id",tempId);
pnodes.item(i).replaceChild(title, nodes.item(j)); // replace the child element, instead of appending
}
}